Question

"What is the energy density (energy per cubic meter) carried by the magnetic field vector in a small region of space in a EM wave at an instant of time when the electric vector is a maximum of 3500V/m

Answer 1

Answer:

The energy density is  $Z = 5.4 2 *10^{-5 } \ J/m^3$

Explanation:

From the question we are told that

    The electric vector is  $E = 3500 \ V/m$

Generally the energy vector is mathematically represented as

      $Z = 0.5 * \epsilon_o * E^2$

Where  $\epsilon_o$ is the permitivity of free space with the value  $\epsilon_o = 8.85*10^{-12} \ \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2$

substituting values

      $Z = 0.5 * 8.85 *10^{-12} * 3500^2$

      $Z = 5.4 2 *10^{-5 } \ J/m^3$