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3 years ago

If a 5 kg bowling ball is lifted to a height of 2 meters, how much potential

Physics

1 answer:

natka813 [3]3 years ago

8 0

Answer:

$\boxed {\boxed {\sf 98.1 \ Joules}}$

Explanation:

The formula for potential energy is:

$E_p=mgh$

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass is 5 kilograms and the height is 2 meters. Assuming this ball is on Earth, then the gravitational acceleration is 9.81 meters per square second.

$m= 5 \ kg \\g= 9.81 \ m/s^2 \\\h= 2 \ m$

Substitute the values into the formula.

$E_p= ( 5 \ kg )(9.81 \ m/s^2)( 2 \ m)$

Multiply the first two numbers.

$E_p=49.05 \ kg*m/s^2 (2 \ m )$

Multiply again.

$E_p= 98.1 \ kg*m^2/s^2$

1 kilogram square meter per square second is equal to 1 Joule.
Our answer is equal to 98.1 Joules

$E_p= 98.1 \ J$

The ball has 98.1 Joules of potential energy.

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4 years ago

Two equal, but oppositely charged particles are attracted to each other electrically. The size of the force of attraction is 48.

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The force of attraction is F = 48.1 N

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To find the magnitude of charge.

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The magnitude of charge can be calculated by the formula

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