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Free_Kalibri [48]
3 years ago
12

If a 5 kg bowling ball is lifted to a height of 2 meters, how much potential

Physics
1 answer:
natka813 [3]3 years ago
8 0

Answer:

\boxed {\boxed {\sf 98.1 \ Joules}}

Explanation:

The formula for potential energy is:

E_p=mgh

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass is 5 kilograms and the height is 2 meters. Assuming this ball is on Earth, then the gravitational acceleration is 9.81 meters per square second.

m= 5 \ kg \\g= 9.81 \ m/s^2 \\\h= 2 \ m

Substitute the values into the formula.

E_p= ( 5 \ kg )(9.81 \ m/s^2)( 2 \ m)

Multiply the first two numbers.

E_p=49.05 \ kg*m/s^2 (2 \ m )

Multiply again.

E_p= 98.1 \ kg*m^2/s^2

  • 1 kilogram square meter per square second is equal to 1 Joule.
  • Our answer is equal to 98.1 Joules

E_p= 98.1 \ J

The ball has 98.1 Joules of potential energy.

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While researching scuba diving, Pablo reads how hot a tank should get while being filled with air. Which law best explains why t
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Answer:

Gay-Lussac’s law, because as the pressure increases, the temperature increases

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First of all, we can notice that the volume of the tank is fixed: this means that the volume of the air inside is also fixed.

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At constant volume, the heat of combustion of a particular compound is − 3550.0 kJ / mol. When 1.075 g of this compound ( molar
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Answer:

C=1,25\cdot 10^{5} kJ/^{\circ}C

Explanation:

First of all let's define the specific molar heat capacity.

C = \frac{-Q}{n\cdot \Delta T} (1)

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Now, we can find n with the molar mass (M) the mass of the compound (m).

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C=\frac{-3550}{6.95\cdot 10^{-3} 4.073}

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I hope it helps!

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