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3 years ago

¿Qué es la velocidad?

Physics

1 answer:

egoroff_w [7]3 years ago

5 0

Velocidad-es una cantidad vectorial física; Tanto la magnitud como la dirección son necesarias para definirlo.

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A person following a liberal ideology would likely approve of

Vinil7 [7]

I’m
not sure sorry :5

4 0

3 years ago

Calculate the momentum of of a 1,5000 kg car traveling at 6 m/s

ANEK [815]

Answer: 90000 kgm/s

Explanation:

Given that,

Momentum of car = ?

Mass of car = 1,5000 kg

Velocity of car = 6 m/s

Recall that momentum is the product of mass of the moving object by its velocity

i.e Momentum = mass x velocity

Momentum = 15000kg x 6m/s

= 90000kgm/s

Thus, the momentum of the car is 90000 kgm/s

4 0

4 years ago

a 230-newton box rests on a plank 5 meters long. One end is 1.2 meters higher than the other end. Find the components of the for

NISA [10]

Answer:

55.3 N, 223.3 N

Explanation:

First of all, we can find the angle of the inclined plane.

We have:

L = 5 m the length of the incline

h = 1.2 m is the height

We also have the relationship

$h = L sin \theta$

where $\theta$ is the angle of the incline. Solving for the angle,

$\theta= sin^{-1} (\frac{h}{L})=sin^{-1} (\frac{1.2 m}{5 m})=13.9^{\circ}$

Now we can find the components of the weight of the box, which is the force that the box exerts on the plank. Calling W = 230 N the weight of the box, we have:

- Component parallel to the incline:

$W_{par} = W sin \theta = (230 N)(sin 13.9^{\circ}) =55.3 N$

- Component perpendicular to the incline:

$W_{per} = W cos \theta = (230 N)(cos 13.9^{\circ}) =223.3 N$

4 0

3 years ago

A monatomic ideal gas initially fills a container of volume V = 0.25 m3 at an initial pressure of P = 250 kPa and temperature T

Murrr4er [49]

Answer:

number of moles = 27.34 moles

the temperature of gas after it undergoes the isobaric expansion = 605 K

Explanation:

Given that:

V = 0.25 m³

P = 250 kPa

T = 275 K

V₂ = 0.55 m³

P₂ = 760 kPa

Using ideal gas equation ; PV = nRT

$n = \frac{PV}{RT}\\\\n = \frac{250*10^3*0.25}{8.314*275}\\\\n = \frac{62500}{2286.35}\\\\n = 27.34 \ moles$

b) To calculate the temperature of gas after it undergoes the isobaric expansion; we have:

$\frac{V_1}{T_1}= \frac{V_2}{T_2}\\\\\frac{0.25}{275}= \frac{0.55}{T_2}\\\\T_2=\frac{0.55*275}{0.25}\\\\T_2 = 605 K$

4 0

4 years ago

Calculate the energy released as heat when 51.60 g Cu 2 O ( s ) undergo oxidation at constant pressure.

lesya692 [45]

Answer:

Energy released as heat will be -189.417 Kj

Explanation:

The oxidation is the type of reaction in which reaction occurs in the presence of oxygen. The exothermic reaction is the type of reaction in which heat is released. The enthalpy is the type of physical quantity that is used to measure the energy in the thermodynamic system.

As we know the molar mass of Copper II Oxide is 79.545 g

Also the oxidation of copper(II) oxide, CuO(s), is an exothermic process, 2Cu2O (s) + O2-->4CuO (s) delta H reaction= -292.0 kj/mol.

So for 51.60g of Copper II Oxide,

Heat released will be (-292.0 * 51.60/79.545) = -189.417 Kj

6 0

3 years ago