Answer:
2.029×10^-18 J
Explanation:
E=hv
so
E=(3.06×10^15)*(6.63×10^-34)
E=2.029×10^-18 J
Answer:
Pressure = 9.94 x 10⁶ Pascals
Explanation:
given data
mass = 51 kg
radius = 0.400 cm
solution
we know Pressure that is express as here
Pressure = total force on an area ÷ the area of the area .................1
and
Force is the woman's weight so weight will be
Weight = mass × gravity .................2
put here value
Weight = 51 × 9.8 m/s²
Weight = 499.8 Newtons
and
Area of a circle of bottom of the heel = (π) × (radius)² ...................3
put here value
Area = (π) × (0.40 cm)²
Area = 0.502654 cm²
Area = 0.0000502654 m²
and
now we put value in equation 1 we get
Pressure = force ÷ area
Pressure = 499.8 ÷ 0.0000502654
Pressure = 9943221.381 N/m²
Pressure = 9.94 x 10⁶ Pascals
Answer:
Final Velocity = 4.9 m/s
Explanation:
We are given;. Initial velocity; u = 2 m/s
Constant Acceleration; a = 0.1 m/s²
Distance; s = 100 m
To find the final velocity(v), we will use one of Newton's equations of motion;
v² = u² + 2as
Plugging in the relevant values to give;
v² = 2² + 2(0.1 × 100)
v² = 4 + 20
v² = 24
v = √24
v = 4.9 m/s
Answer:
The induced current is 26.7 mA
Explanation:
Given;
area of the loop, A = 0.078 m²
initial magnetic field, B₁ = 3.8 T
change in the magnetic field strength, dB/dt = 0.24 T/s
The induced emf is calculated as;
The resistance of the loop = 0.7 Ω
The induced current is calculated as;
When the body is at rest, its speed is zero, and the graph lies on the x-axis.
When the body is in uniform motion, the speed is constant, and the graph is a horizontal line, parallel to the x-axis and some distance above it.
It's impossible to tell, based on the given information, how these two parts of the
graph are connected. There must be some sloping (accelerated) portion of the graph
that joins the two sections, but it cannot be accounted for in either the statement
that the body is at rest or that it is in uniform motion, since acceleration ... that is,
any change of speed or direction ... is not 'uniform' motion'.
