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Evgen [1.6K]
3 years ago
11

Please help ASAP. How is heat related to work?

Physics
1 answer:
earnstyle [38]3 years ago
7 0
Energy is the ability to do work so I would say that thermal or heat energy is a type of work. Don’t know if this will work but that’s what I would put.
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2. a) A disc rotates about its axis at speed 25 revolutions per minute and takes 15 s to stop. Calculate the
ASHA 777 [7]

The statement shows a case of rotational motion, in which the disc <em>decelerates</em> at <em>constant</em> rate.

i) The angular acceleration of the disc (\alpha), in revolutions per square second, is found by the following kinematic formula:

\alpha = \frac{\omega_{f}-\omega_{o}}{t} (1)

Where:

  • \omega_{o} - Initial angular speed, in revolutions per second.
  • \omega_{f} - Final angular speed, in revolutions per second.
  • t - Time, in seconds.

If we know that \omega_{o} = \frac{5}{12}\,\frac{rev}{s}, \omega_{f} = 0\,\frac{rev}{s} y t = 15\,s, then the angular acceleration of the disc is:

\alpha = \frac{0\,\frac{rev}{s}-\frac{5}{12}\,\frac{rev}{s}}{15\,s}

\alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}

The angular acceleration of the disc is \frac{1}{36} radians per square second.

ii) The number of rotations that the disk makes before it stops (\Delta \theta), in revolutions, is determined by the following formula:

\Delta \theta  = \frac{\omega_{f}^{2}-\omega_{o}^{2}}{2\cdot \alpha} (2)

If we know that \omega_{o} = \frac{5}{12}\,\frac{rev}{s}, \omega_{f} = 0\,\frac{rev}{s} y \alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}, then the number of rotations done by the disc is:

\Delta \theta = 3.125\,rev

The disc makes 3.125 revolutions before it stops.

We kindly invite to check this question on rotational motion: brainly.com/question/23933120

6 0
3 years ago
What makes a ship float​
stellarik [79]

Answer:

Ships can float because a ship is less dense than that of the water that it floats on.

Explanation:

Hope this helps!

7 0
3 years ago
A solid metal object hangs from a force sensor by a thread in the open air, and the actual weight is measured to be 0.71 N. Then
Alexeev081 [22]

Answer:

The apparent weight of the object is 0.465 N.

Explanation:

Given that,

Weight = 0.71 N

Water level = 50 mL

object inserted = 75 mL

We need to calculate the volume of solid

Using formula of volume

V=25\ ml = 25\times10^{-6}\ m^3

We need to calculate the buoyancy force

Using formula of buoyancy force

F'= V\rho g

Put the value into the formula

F'=25\times10^{-6}\times1000\times9.8

F'=0.245\ N

We need to calculate the apparent weight of the object

Using formula of apparent weight

W=F-F'

Put the value into the formula

W=0.71-0.245

W=0.465\ N

Hence, The apparent weight of the object is 0.465 N.

5 0
3 years ago
How far is the Earth from the Sun?
ohaa [14]

Answer:93.431 million mi

Explanation:

google lol

4 0
3 years ago
Read 2 more answers
Calculate the force between charges of 5.0 x 10^-8 c and 1.0 x 10^-7 if they are 5.0 feet apart
weqwewe [10]

Answer:

F = 19.375 x 10^-6  N

Explanation:

This problem can be solved by applying Coulomb's Law, which lets us determine the force between two electrically charged particles.

It is defined as

F = (ke * q1 * q2)/ r^2

Where,

ke =  is Coulomb's constant ≈ 9×10^9 N⋅m^2⋅C^−2

q1 = 5.0 x 10^-8 C

q2 = 1.0 x 10^-7 C

r = 5 ft = 1,524 m

F  = (9×10^9 N⋅m^2⋅C^−2)*(5.0 x 10^-8 C)*(1.0 x 10^-7 C)/ ((1,524 m)^2)

F  = (9×10^9 N⋅m^2⋅C^−2)*(5.0 x 10^-8 C)*(1.0 x 10^-7 C)/ ((1,524 m)^2)

F = 19.375 x 10^-6  N

6 0
3 years ago
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