The force applied to the second ball by the first ball is 6.734 × 10^-4 N.
<h3>What is impulse of force?</h3>
The impulse of force is defined as the sum of the average force and the duration it is applied.
If the mass of the item remains constant, the impulse of force equals the change in momentum of the object.
Given that: mass of a metal sphere: m = 0.026 kg.
Initial speed of the sphere: u = 3.7 m/s.
When the sphere stops completely, its change in momentum = mu - 0
= 0.026×3.7 N-s.
= 0.0962 N-s.
As the spheres are in contact for 0.007s before the second sphere is shot off down the track, the force applied to the second ball =
change in momentum of 1st ball × time of contact
= 0.0962 × 0.007 N
= 0.0006734 N
= 6.734 × 10^-4 N.
Hence, the force applied to the second ball is 6.734 × 10^-4 N.
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Answer:
ummmmmmmmmm through science??
4x time 10x (I think)
Here, this will help-
http://www.cas.miamioh.edu/mbiws/microscopes/Magnification.html#totalmagnification
Answer:
I not sure I need more info to answer this specific question I'm sorry
Answer:
Image is between F and 2F. And the exact location is:
q = 10.84 cm
Explanation:
The convex lens form different kinds of images with different sizes and locations, for the different positions of an object. In this case, the object is placed 30.5 cm from the convex lens with a focal length of 8 cm. This means that it is the case of the object placed beyond 2F. In this case, the image formed has the following characteristics:
1. Image is real.
2. Image is inverted
3. Image is diminished
<u>4. Image is located between F and 2F</u>
For exact location we use the thin lens formula:
where,
f = focal length = 8 cm
p = object distance = 30.5 cm
q = image distance = ?
Therefore,
<u>q = 10.84 cm</u>
