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Natasha_Volkova [10]
3 years ago
6

Find the unknown side

Physics
1 answer:
Lorico [155]3 years ago
8 0

Answer:

75

Explanation:

Here,

Hypotenuse (h)= X

base (b)= 72

perpendicular(p)=21

Now, h2=P2 + B2

x2 = (21×21) + (72×72)

x2= 441 + 5184

x2= 5625

X= √ 5625

X= 75

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Materials will have different energies associated with the electrons inside them. This is related to how strongly bound they are
andrey2020 [161]

Answer:

E = 401.3 eV

Explanation:

As we know that the thinnest gap in the direction of metal is given as

t = 3.09 nm

so here we can say that lowest energy of photon will not able to break this electron from above thickness

so we will have

E = \frac{hc}{\lambda}

here we have

hc = 1240 nm-eV}

also we have

\lambda = 3.09 nm

so we will have

E = \frac{1240}{3.09} eV

E = 401.3 eV

7 0
4 years ago
A railroad cart with a mass of m1 = 11.6 t is at rest at the top of an h = 10.9 m high hump yard hill.
leonid [27]

The final common speed of the two carts will be 69.3 m/sec.The momentum conservation principle is applied.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

Unit conversion:

1 metric tons = 1000 kg

Given data;

m₁= 11.6 metric ton =11600 kg

m₂ = 23.2 metric ton =  23200 kg

Let v represent the combined velocity of the two carts once they are connected, and let u represent the starting velocity of cart 1 when it reaches the bottom.

Considering energy conservation;

\rm  m_1 g h = \frac{1}{2} m_1 \times  u^2 \\\\ u^2 = 2gh\\\\ u^2 = 2  \times 9.8 \times 10.6 \\\\  u = 207.972 \ m/s

From the conservation of momentum principle;

\rm m_1 \times  u = (m_1 + m_2) v\\\\ 11600 \times  207.972 = (11600 + 23200) \times v \\\\ v = 69.3  \ m/s

Hence, the final common speed of the two carts will be 69.3 m/sec.

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

#SPJ1

7 0
2 years ago
In order to do work, the force vector must be
gregori [183]

As we know that total work done by a force is given by

W = F.d

W = Fdcos\theta

so it is product of force and displacement along same direction

as we can write it as

W = (Fcos\theta)(d)

so it must be the product of force and displacement in same directions so correct answer must be

<u>B. in the same direction as the displacement vector and the motion.</u>

6 0
3 years ago
Read 2 more answers
HELP PLSSS
Andrews [41]

Given :

A 13.3 kg box sliding across the ground  decelerates at 2.42 m/s².

To Find :

The coefficient of kinetic friction.

Solution :

Frictional force applied to the box is :

f = ma    ....1)

Also, force of friction is given by :

f = \mu mg  ....2)

Equating equation 1) and 2), we get :

\mu mg = ma\\\\\mu = \dfrac{a}{g}\\\\\mu = \dfrac{2.42}{9.8}\\\\\mu = 0.247

Therefore, the coefficient of kinetic friction is 0.247 .

8 0
3 years ago
QUESTION 16
erica [24]

Answer:

20 characters

Explanation:

6 0
3 years ago
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