moles of hydrogen in reaction =
=
= 0.996 mol
ratio of
: Na is 1 : 2
∴ if mol of
= 0.996 mol
then mol of Na = (0.996 mol * 2)
= 1.99 mol
Mass of Na = molar mass * mol
= (22.99 g / mol) * (1.99 mol)
= 45.78 g
Note:
1) Molar Mass is the mass of an element measured in grams.
2) According to Avogadro's Law, the same volume of different gases at the same condition of Temperature and Pressure contain the same number of particles. From this law we know that at STP, one mole of gas occupies 22.4 L of volume (molar volume).
3) By calculating the mole of one specie in a reaction, one can use mole ratio based on the stoichimectric values (values used to balance the equation) given to the species upon balancing the equation to find the moles of another species.
Answer: A
Explanation:
Considering the order of filling electrons into orbitals, movement from a higher to a lower energy level results in the emission of a photon with energy equal to the energy difference between the two energy levels. However, the energies of different orbitals are close together for high values of n (principal quantum number). Their relative energies may change significantly when they form ions. This implies that energy levels are better separated and have high differences in energy for low values of n. Hence the answer. This means that photons transiting between these Lowe n levels will posses higher photon energy due to larger energy difference between levels.
Carbohydrates is a amino acid
In the stomach cell, the enzyme carbonic anhydrase converts one molecule of carbon dioxide and one molecule of water indirectly into a bicarbonate ion (HCO3-) and a hydrogen ion (H+). In the stomach ion exchange is used to move H+ ions out the cells and into the lumen of the stomach
Answer:
C
Explanation:
We know that the molar mass of KOH is 56 gmol-1
Molar mass of Mg(OH)2 is 58.31 g/mol
Now; the balanced reaction equation is; MgCl2 + 2KOH → Mg(OH)2 + 2KCI
Hence;
2 moles of KOH yields 1 mole of Mg(OH)2
4 moles of KOH yields;
4 moles of KOH/1 mol * 1 mole Mg(OH)2 /2 moles KOH * 58.31 g Mg(OH)2 / 1 mole Mg(OH)2
So option c is correct
