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timurjin [86]
3 years ago
13

What would be the formula of the compound iron (III) phosphide?

Chemistry
2 answers:
goldfiish [28.3K]3 years ago
8 0
The chemical formula of iron phosphide would be Fe3P. 
irina1246 [14]3 years ago
7 0
<span>Fe3P 
hope it help's you 


</span>
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Which of the following statements is true?
Lera25 [3.4K]

The  statement  which is true is

metals  lose  electrons  to become cations

<u><em>Explanation</em></u>

  • metals tends  to loss electrons to attain  noble gas  electrons  configuration.
  • When metal loses electrons they form a  positive charged ions.
  • The positively charged ion is known as  cations.
  • for  example  sodium metal (Na)  loses  1 electron to form   a cation with  a charge  of positive 1 ( Na^+)
3 0
3 years ago
Read 2 more answers
Which index fossil is most likely to be found in<br> the Allegheny Plateau?
Usimov [2.4K]

Answer:

amphibians

Explanation:

please mark this answer as brainliest

5 0
3 years ago
If an atom has 11 protons and 13 neutrons what is it’s atomic number
Travka [436]

Answer:

the atomic number is 11 and element is Sodium (Na)

Explanation:

Number of Protons = Number of Electrons = 11

Number of Neutrons = 13

Here, the Number of Protons and Number of Electrons is 11

So,

the atomic number is <em><u>11</u></em> and element is <em><u>Sodium </u></em><em><u>(</u></em><em><u>Na) </u></em>

5 0
3 years ago
For the following reaction, 7.53 grams of benzene (C6H6) are allowed to react with 8.33 grams of oxygen gas. benzene (C6H6) (l)
juin [17]

Answer:

The maximum amount of CO2 that can be formed is 9.15 grams CO2

O2 is the limiting reactant

There will remain 4.82 grams of benzene

Explanation:

Step 1: Data given

Mass of benzene = 7.53 grams

Mass of oxygen gas = 8.33 grams

Molar mass of benzene = 78.11 g/mol

Molar mass oxygen gas = 32.00 g/mol

Step 2: The balanced equation

2C6H6 + 15O2 → 12CO2 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles C6H6 = 7.53 grams / 78.11 g/mol

Moles C6H6 = 0.0964 moles

Moles O2 = 8.33 grams / 32.00 g/mol

Moles O2 = 0.2603 moles

Step 4: Calculate the limiting reactant

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.2603 moles). Benzene is in excess. there will react 2/15 * 0.2603 = 0.0347 moles

There will remain 0.0964 - 0.0347 = 0.0617 moles benzene

This is 0.0617 moles * 78.11 g/mol = <u>4.82 grams benzene</u>

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Step 5: Calculate moles CO2

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

For 0.2603 moles O2 we'll have 12/15 * 0.2603 = 0.208 moles CO2

Step 6: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.208 moles * 44.01 g/mol

<u>Mass CO2 = 9.15 grams</u>

4 0
3 years ago
How much heat would need to be absorbed for 40g of ice to melt?
Eddi Din [679]

Answer:

- 19501130 dhakdjsu dhakdjsu 2

Explanation:

3 0
3 years ago
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