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shepuryov [24]
3 years ago
7

What is the name of the compound Cd(MnO4)2?

Chemistry
1 answer:
allochka39001 [22]3 years ago
5 0
C ) cadmium permanganate
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OK! this is for the weebs :D
maw [93]

Answer:

Explanation:3

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Which of the following describes an ionic bond?
nydimaria [60]
C because it is and I know
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Which electron configuration represents the electrons of an atom in an excited state? * 2-3 2-7-1 2-8 2-8-1​
Lemur [1.5K]

2-7-1

<h3>Further explanation </h3>

Electrons can move the shell up or down by releasing energy or absorbing energy  

Excited electrons show higher electron transfer to the shell by absorbing energy  

So it can be concluded that there are 2 conditions:  

Ground state is the state of electrons filling shell with the lowest energy levels.  

Excited state is the state of electrons which occupies a higher energy level  

The state of excited electrons can be seen from the presence of electrons which do not fill the skin completely but fill the skin afterward  

2-7-1

From its 8 electron configuration, filling 3 shells, 2 electrons in the firs shell, 7 electrons in the second shell and 1 electron in the third shell

the electrons in the third shell should fill the electrons in the second shell first according to Aufbau rule (lower energy shells)

\tt  1s^22s^22p^4\rightarrow ground~state\\\\1s^22s^22p^33s^1\rightarrow excited~state

8 0
3 years ago
Cycle. Then you will watch an animated model of the cycle.
scoundrel [369]

Answer:

number 1

Explanation:

i think

3 0
3 years ago
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If you have 5.42 x 1024 aluminum atoms, approximately how many moles is that
sattari [20]

Answer:

<h2>9.00 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{5.42 \times  {10}^{24} }{6.02 \times {10}^{23} }  \\  = 9.0033

We have the final answer as

<h3>9.00 moles</h3>

Hope this helps you

4 0
3 years ago
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