The balanced reaction equation for the reaction between CH₃OH and O₂ is 2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(l) Initial moles 12 24 Reacted moles 12 18 Final moles - 6 12 24
The stoichiometric ratio between CH₃OH and O₂ is 2 : 3 Hence, reacted moles of O₂ = reacted moles of CH₃OH x (3/2) = 12 mol x 3 / 2 = 18 mol
All of CH₃OH moles react with O₂.
Hence, the limiting agent is CH₃OH.
Excess reagent is O₂. Amount of moles of excess reagent left = 24 - 18 mol = 6 mol