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Bingel [31]
3 years ago
14

A sphere is charged with electrons to

Physics
1 answer:
hammer [34]3 years ago
4 0

Answer:

4.38\cdot 10^{13} electrons

Explanation:

The net charge on the sphere is equal to:

Q=-7\cdot 10^{-6}C

This charge is made up of N electrons. Each electron carries a charge of

q=-1.6\cdot 10^{-19}C

So the total charge is just the number of electrons times the charge of each electron:

Q=Nq

And solving the equation for N, we find the number of electrons:

N=\frac{Q}{q}=\frac{-7\cdot 10^{-6}C}{-1.6\cdot 10^{-19} C}=4.38\cdot 10^{13}

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An airplane has an effective wing surface area of 19.4 m2 that is generating the lift force. In level flight the air speed over
alexgriva [62]

Answer:

W =23807.68 N

Explanation:

given,

surface area of wing = 19.4 m²

speed over top wing = 67 m/s

speed under wing = 51 m/s

density of air =  1.3 kg/m³

weight of plane

From Bernoulli's principle

P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho_2^2

where 1 and 2 are two different locations at the same geo potential level  

so if we call 1 the lower surface and 2 the upper surface,

we find the pressure differential, P₁ -P₂

\Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)

\Delta P =\dfrac{1}{2}\times 1.3 \times (67^2-51^2)

\Delta P =1227.2\ N/m^2

then the force acting on the plane is

F=P A

F=1227.2 x 19.4

F =23807.68 N

weight of the plane

W =23807.68 N

7 0
3 years ago
Lus
patriot [66]

Answer:

hey but the person at the top is right

7 0
3 years ago
What<br> must always be<br> included on the<br> graph
Nookie1986 [14]
Clearly visible data points and appropriate labels on each access that include units
4 0
3 years ago
A star is moving away from an observer. Toward which end of the spectrum does its visible light shift?.
scZoUnD [109]

Answer:

Redshift, or lower power

Explanation:

doppler effect

waves get stretched when you are moving away from something, and squished when you are moving towards it. Imagine you have a long, bent wire. if you stretch out the wire, the wavelength becomes longer. This also applies to sound.

4 0
2 years ago
In a game of basketball, a forward makes a bounce pass to the center. The ball is thrown with an initial speed of 4.8 m/s at an
tensa zangetsu [6.8K]
The equation to be used here is the trajectory of a projectile as written below:

y = xtanθ +/- gx²/2v²(cosθ)²
where
y is the vertical distance
x is the horizontal distance
θ is the angle of trajectory or launch angle
g is 9.81 m/s²
v is the initial velcity

Since the angle is below horizontal, let's use the minus equation. Substituting the values:

- 0.8 m = xtan15° - (9.81 m/s²)x²/2(4.8 m/s)²(cos15°)²
Solving for x,
x = 2.549 m

However, we only take half of this distance because it was specified that the distance asked before bouncing. Hence, the horizontal distance is equal to 1.27 m.
5 0
4 years ago
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