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DiKsa [7]
3 years ago
5

How much energy is needed to perform 300 J of work?

Physics
1 answer:
4vir4ik [10]3 years ago
3 0
I think this is the answer hope it helps

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An experimental tungsten light bulb filament has a length of 5 cm and a diameter of 0.074 cm. The filament is basically just a w
adell [148]

Answer:

power emitted is 1.75 W

Explanation:

given data

length l = 5 cm = 5 ×10^{-2} m

diameter d = 0.074 cm = 74 ×10^{-5} m

total filament emissivity = 0.300

temperature = 3068 K

to find out

power emitted

solution

we find first area that is π×d×L

area = π×d×L

area = π×74 ×10^{-5}×5 ×10^{-2}

area = 1162.3892  ×10^{-5} m²

so here power emitted  is express as

power emitted  = E × σ × area × (temperature)^4

put here all value

power emitted  = 0.300× 5.67 × 1162.3892  ×10^{-5}  × (3068)^4

power emitted = 1.75 W

5 0
3 years ago
How do i solve?<br><br>a = bc<br>(b)​
stira [4]
I don’t even know I’m so dumb.
7 0
3 years ago
An electric toaster is rated 1200 watts at 120 volts. what is the total electrical energy used to operate the toaster for 30 sec
Anarel [89]
Energy is calculated as power*time, so give the wattage of 1200 W (equivalent to 1200 Joules/second) and time of 30 seconds, multiplying these gives 36000 J or 36 kJ of electrical energy.

If electrical charge or current is needed: Power = voltage * current, so given the power of 1200 watts and voltage of 120 V, current is 1200 W / 120 V = 10 Amperes. Charge is calculated by multiplying 10 A*30 s = 300 C.
3 0
3 years ago
The purpose of _______'s ministry was to bring the nation in exile back to the God of their covenant
Anit [1.1K]
The answer would be Jeremiah
6 0
3 years ago
Read 2 more answers
A string, 30 cm long and having a mass of 45 g, is attached to a 810 Hz oscillator at one end. The other end of the string is fi
Karolina [17]

Answer:

870 N

Explanation:

The expression for velocity of wave in a string is given below

v = \sqrt{\frac{T}{m} }  , T is tension and m is mass per unit length .

m = 45 x 10⁻³ / 30 x 10⁻²

= .15 kg/m

Putting the given values in the equation

76 = \sqrt{\frac{T}{.15} }

T = 76² x .15

= 866.4

870 N  approx.

3 0
3 years ago
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