The correct answer is Reagan is right because sound waves are compressional waves.
Reason is because Sound is transmitted through gases, plasma, and liquids as longitudinal waves, also called compression waves. It requires a medium to propagate. Through solids, however, it can be transmitted as both longitudinal waves and transverse waves.
Answer:
-14.67
Explanation:
this is the answer because Calculating acceleration involves dividing distance by time, so now you to the opposite and multiply the acceleration times 9.
Answer:
Venus
Explanation:
Venus is the second plate in the solar system. It is a terrestrial planet and it is part of the inner rocky planets.
In Venus, it rains sulfuric acid but the rain never reaches the surface before it becomes evaporated. The acid forms from the combination of sulfur oxide and water in the atmosphere at a height of about 42km. As it condenses and falls, it becomes evaporated back at lower elevations. The surface is therefore protected from the sulfuric acid rain.
The sulfur oxide and water vapor must have been derived from volcanic activities in geologic times past.
Answer:
13.2m/s²
1.89s
Explanation:
Given parameters:
Initial velocity = 0m/s
Final velocity 1 = 45m/s
Final velocity 2 = 70m/s
Unknown:
Time taken = 3.4s
Solution:
Acceleration is the rate of change of velocity with time.
Acceleration =
Acceleration =
= 13.2m/s²
B. How much longer would it take the car to get up to 70m/s
Maintaining the is acceleration;
13.2 =
25 = 13.2t
t = 1.89s
<span>The sum of the speeds is 9.44 m/s + 9.44 m/s which is 18.88 m/s
Note that the sum of the speeds of the two stones is always 18.88 m/s because as the upward moving stone loses speed, the downward moving stone gains the same amount of speed each unit of time.
We can find the time for the stones to meet.
t = d / v
t = 5.39 m / 18.88 m/s
t = 0.285487 seconds
We can use the upward moving stone to find the height y.
y = v0 t + (1/2) a t^2
y = (9.44 m/s)(0.285487 s) - (1/2) (9.8 m/s^2) (0.285487 s)^2
y = 2.30 m
The two stones cross paths a height of 2.30 meters above the base of the cliff.</span>