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velikii [3]
3 years ago
5

Write an equation for the reaction of solid aluminum metal with hydrochloric acid (hydrogen monochloride) dissolved in water to

form aluminum chloride dissolved in water and hydrogen gas. When balanced, what is the coefficient for the hydrochloric acid (hydrogen monochloride)?
Chemistry
1 answer:
nydimaria [60]3 years ago
5 0

Answer:

The coefficient for the hydrochloric acid is 6.

Explanation:

Stoichiometric coefficient are the number written in front of the reactants and products in balanced chemical reaction.

When solid aluminum reacts with hydrochloric acid to give aluminum chloride and hydrogen gas.

2Al(s)+6HCl(s)\rightarrow 2AlCl_3(aq)+3H_2(g)

The coefficient for the aluminum is 2.

The coefficient for the hydrochloric acid is 6.

The coefficient for the aluminum chloride acid is 2.

The coefficient for the hydrogen gas  is 3.

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How many moles are in 10 mg of NO2
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If an insect population increases and then decreases as the available supply of food changes, what does this demonstrate
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7 0
3 years ago
Suppose that a certain fortunate person has a net worth of $77.0 billion ($). If her stock has a good year and gains $3.20 billi
marissa [1.9K]

Answer:

New net worth to three significant figures = $80.2 billion

Dollars are given to charity = $100,250,000

Explanation:

Net worth = $77.0 billion

stock Gains = $3.20 billion

New net worth = $77.0 billion + $3.20 billion = $80.20 billion

New net worth to three significant figures = $80.2 billion

One-eighth of a percent = (1/8 x 1) / 100 = 0.00125

Dollars are given to charity = 0.00125 X $80.2 billion = $100,250,000

Or

$80,200,000,000/100 = $802,000,000

3 0
4 years ago
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
3 years ago
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