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Firlakuza [10]
3 years ago
6

Write the correct term: In gaseous substances, the individual molecules are relatively (close/far apart) and are moving freely,

rapidly, and randomly.
Chemistry
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

far apart

Explanation:

The molecules of any gaseous compounds are loosely bound and the molecules are far apart from each other. They move freely and rapidly. The inter-molecular forces are lower as compared to a solid or a liquid where the molecules are comparatively closely bound in the compounds.  

Because of the large gap or distance between its molecules, gaseous compounds have less density  when compared to any solid or liquid.

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A sample of argon gas has a volume of 795 mL at a pres-sure of 1.20 atm and a temperature of 116 ∘C. What is the final volume of
jek_recluse [69]

<u>Answer:</u> The volume when the pressure and temperature has changed is 1.6\times 10^2mL

<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1,V_1\text{ and }T_1 are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2 are the final pressure, volume and temperature of the gas

Let us assume:

P_1=1.20atm\\V_1=795mL\\T_1=116^oC=[116+273]K=389K\\P_2=0.55atm\\V_2=?mL\\T_2=75^oC=[75+273]K=348K

Putting values in above equation, we get:

\frac{1.20atm\times 795mL}{389K}=\frac{0.55atm\times V_2}{348K}\\\\V_2=\frac{1.20\times 795\times 348}{0.55\times 389}=1.6\times 10^3mL

Hence, the volume when the pressure and temperature has changed is 1.6\times 10^2mL

5 0
3 years ago
Calculate the work (kJ) done during a reaction in which the internal volume expands from 20 L to 43 L against an outside pressur
Alenkinab [10]

Answer:

\large \boxed{\text{-10.0 kJ}}

Explanation:

1. Calculate the work

w = - pΔV = -4.3 atm × (43 L - 20 L) = -4.3 × 23 L·atm = -98.9 L·atm

2. Convert litre-atmospheres to joules

w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}

The negative sign indicates that the work was done against the surroundings.

4 0
3 years ago
In most cases, reactant-favored reactions have:​
vekshin1

Answer:

Have negitive values

Explanation:

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What is the Chemical formula for K and P
gayaneshka [121]

Answer:

Potassium phosphide (K3P)

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3 years ago
Poh of a solution with a ph of 5.00
creativ13 [48]

Answer:

9

Explanation:

14-5.=pOH

- Hope that helps! Please let me know if you need further explanation.

8 0
3 years ago
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