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timofeeve [1]
2 years ago
5

The triangles shown below must be congruent. False True

Mathematics
2 answers:
fgiga [73]2 years ago
6 0
True congruent means the same
Aneli [31]2 years ago
5 0

Answer:

true. They are the same shape and same size.

Step-by-step explanation:

You might be interested in
FILL IN THE BLANKS AND TELL ME WHAT THEY ARE!!!! HELP ASAP!!! FIRST PERSON GETS BRAINLIEST ANSWER!! NO LINKS! ASAP!!
photoshop1234 [79]

9514 1404 393

Answer:

  • no solutions
  • 1, 14=0
  • 2, 7=0

Step-by-step explanation:

The first blank is correctly filled with "no solutions."

The two requested values of x can be <em>any numbers of your choice</em> (except 0). Above, we have chosen x=1, which makes the equation 14/1 = 0, or 14 = 0 when simplified.

And we have chosen x=2, which makes the equation 14/2 = 0, or 7 = 0 when simplified.

__

In short, there are <em>an infinite number of correct answers</em> to this question.

8 0
3 years ago
Andrea does not understand why if x is a solution to the equation 3-x=4 then x is also a solution to the equation 12=9-3x. Write
Strike441 [17]

Answer:

Both equations are same

Step-by-step explanation:

The reason why this is true is not far fetched

looking at the first equation, we have;

3-x = 4

we can also factorize the second equation to look this way

By this, we shall be having

3(4) = 3(3-x)

By the time we take out the 3 from both sides, we will have the initial equation

So what we are saying is that both equations are the same

6 0
3 years ago
A-5-B when A=9 and B=-4
Fed [463]

Answer:

8

Step-by-step explanation:

(Refer to picture)

Plug in the value of A and the value of B into the expression

3 0
4 years ago
Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x
Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

y=a(x-h)^2+k  

(where (h, k) is the vertex)

Given:

  • vertex = (1, -108)

\implies y=a(x-1)^2-108

Given:

  • y-intercept = (0, -105)

\implies a(0-1)^2-108=-105

\implies a(-1)^2=-105+108

\implies a=3

Therefore:

\implies y=3(x-1)^2-108

The x-intercepts are when y = 0

\implies 3(x-1)^2-108=0

\implies 3(x-1)^2=108

\implies (x-1)^2=36

\implies x-1=\pm \sqrt{36}

\implies x=1\pm 6

\implies x=7, x=-5

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0
2 years ago
A network provider investigates the load of its network. The number of concurrent users is recorded at fifty locations (thousand
beks73 [17]

Answer:

see explaination

Step-by-step explanation:

Using the formulla that

sum of terms number of terms sample mean -

Gives the sample mean as \mu=17.954

Now varaince is given by

s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97

and the standard deviation is s=\sqrt{9.97}=3.16

b) The standard error is given by

\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45

c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1

Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88

d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05

Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96

or a number which is less than 15.83-1.5(4.05)=9.76

As there is no such number so the given sample has no outliers

5 0
3 years ago
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