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Ann [662]
3 years ago
11

A star's mass determines the —

Chemistry
1 answer:
kvasek [131]3 years ago
6 0
It’s either A or C sorry I can’t help more
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They are classified differently and they have a different outer skin structure: scales 
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Entropy change in an internally reversible isothermal process is _______ to the temperature of the system.
alukav5142 [94]

Answer:

Internally reversible is the answer.

Explanation:

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3 years ago
How many moles of gas would occupy 22.4 L at 273K in one arm?
andrew-mc [135]

Answer:

1 mol

Explanation:

Using the general gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the provided information in the question;

V = 22.4L

T = 273K

P = 1 atm

R = 0.0821 Latm/molK

n = ?

Using PV = nRT

n = PV/RT

n = (1 × 22.4) ÷ (0.0821 × 273)

n = 22.4 ÷ 22.4

n = 1mol

4 0
2 years ago
Why are gamma rays not affected by a magnet as they Passover it
avanturin [10]
Gamma rays are not magnetic
7 0
3 years ago
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If we have three different solutions, A, B, and C, each containing 100 g of water, plus respectively 6.84 g of sucrose (C12H22O1
GenaCL600 [577]

Answer:

c. A and C have the same boiling point, but B has a lower one.

Explanation:

The freezing point depression is expressed as:

ΔT = kf×m

Where kf is the freezing point depression constant that depends the nature of the solvent and m is molality (mol of solute/kg of solvent)

Boiling point elevation is:

ΔT = kb×m

Where kb is the ebulloscopic constant of the solvent.

As kf, kb and mass of solvent is the same for A, B and C solutions the only difference will be in moles of solute.

<em>A </em>6,84g of sucrose are:

6,84g×\frac{1mol}{342,3g} = <em>0,002 moles</em>

<em>B </em>0,72g of ethanol are:

0,72g×\frac{1mol}{46,1g} = <em>0,0016 moles</em>

<em>C </em>0,40g of sodium hydroxide are:

0,40g×\frac{1mol}{40g} = <em>0,001 moles</em>

Using Van't Hoff factor that describes the number of moles in solution that comes from 1 mole of solute before dissolving, moles in solution for A, B and C are:

A. moles in solution: 0,02 moles×1 = <em>0,02 moles in solution</em>

B. moles in solution: 0,016 moles×1 = <em>0,016 moles in solution</em>

C. moles in solution: 0,01 moles×2 = <em>0,02 moles in solution</em>

As A has the same moles in solution of C, the freezing point depression will be the same in A and C, and the lower freezing point depression will be in B.

Also, the boiling point will be higher in A and C, and then in B.

Thus:

a. C has the lowest freezing point in the group.  <em>FALSE. </em>A and C have the lowest feezing point because have the higher freezing point depression.

b. A, B, and C all have different freezing points.  <em>FALSE. </em>As moles of A and C are the same, freezing point will be the same for the solutions.

c. A and C have the same boiling point, but B has a lower one.  <em>TRUE. </em>

d. The boiling point of C is lower than that of A or B . <em>FALSE. </em>Boiling point of C and A is higher than B.

e. A, B, and C will all have about the same freezing points. <em>FALSE</em>

7 0
3 years ago
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