Answer:
The correct answer is option 1 "F(2-) "less than" C2(2+) "less than" O(2-) "less than" N(2-)".
Explanation:
Bond order is a term used in chemistry to identify the number of electrons involved in making the bonding between two or more atoms in a molecule. Bond order is equal to half the difference between the number of bonds in the atoms minus the number of antibonds. Therefore, the correct order of bond order from smallest to largest is as follows:
1. F(2-): equals to 0.5 (it has 8 bonds and 7 antibonds)
2. C2(2+): equals to 1 (it has 4 bonds and 2 antibonds)
3. O(2-): equals to 2 (it has 8 bonds and 4 antibonds)
4. N(2-): equals to 2.5 (it has 8 bonds and 3 antibonds)
Answer:
The ability for a pond to freeze over in the winter is a physical property.
Answer:
I think the answer is distilled water...
Explanation:
The molarity of the acid sample H₂SO₄ is 0.052M .
<h3>What is Molarity ?</h3>
Molarity (M) is the amount of a substance in a certain volume of solution.
Molarity is defined as the moles of a solute per liters of a solution.
Molarity is also known as the molar concentration of a solution
Now to determine the molarity of the acid sample
V( H₂SO₄) = 24.0 mL in liters = 24.0 / 1000 = 0.024 L
M(H₂SO₄) = ?
V(NaOH) = 20.0 mL = 20.0 / 1000 = 0.02 L
M(NaOH) = 0.125 M
Number of moles NaOH :
n = M x V
n = 0.125 x 0.02
n = 0.0025 moles of NaOH
H₂SO₄(aq) + 2 NaOH(aq) = Na₂SO₄(aq) + 2 H₂O(l)
1 mole H₂SO₄ ---------- 2 mole NaOH
? mole H₂SO₄ ---------- 0.0025 moles NaOH
moles = 0.0025 * 1 / 2
= 0.00125 moles of H₂SO₄
M(H₂SO₄) = n / V
M = 0.00125 / 0.024
= 0.052 M
Therefore the molarity of the acid sample H₂SO₄ is 0.052M .
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<h2><em><u>
Answer - </u></em>b) Be the same as in the second method</h2>
<h3>Brief explanation:</h3>
Enthalpy is an state function that does not depend on the path followed to carry out the reaction but depends upon the initial and final state of system. In above statement both the reaction are same hence the enthalpy change would also be same. This can also be represent in the form of equation,
<h3> ΔHsys = Hf - Hi</h3>
Where,
- ΔHsys is change in enthalpy of system
- Hf is enthalpy of reaction at final state
- Hi is enthalpy of reaction at initial state
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