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weeeeeb [17]
4 years ago
7

onsider what happens when you jump up in the air. Which of the following is the most accurate statement?A) Since the ground is s

tationary, it cannot exert the upward force necessary to propel you into the air.Instead, the internal forces of your muscles acting on your body itself propels the body into the air.B) The upward force exerted by the ground pushes you up, but this force can never exceed your weight.C) When you jump up the earth exerts a force F1on you and you exert a force F2 on the earth. You go upbecause F1 > F2, and this is so because F1 is to F2 as the earth's mass is to your mass.D) You are able to spring up because the earth exerts a force upward on you which is stronger than thedownward force you exert on the earth.E) When you push down on the earth with a force greater than your weight, the earth will push back with thesame magnitude force and thus propel you into the air.
Physics
1 answer:
Likurg_2 [28]4 years ago
5 0

Answer: D

Explanation: it seem right to me I really don't know if this right but I hope this helps

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A car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver n
satela [25.4K]

Answer:

a) t1 = v0/a0

b) t2 = v0/a0

c) v0^2/a0

Explanation:

A)

How much time does it take for the car to come to a full stop? Express your answer in terms of v0 and a0

Vf = 0

Vf = v0 - a0*t

0 = v0 - a0*t

a0*t = v0

t1 = v0/a0

B)

How much time does it take for the car to accelerate from the full stop to its original cruising speed? Express your answer in terms of v0 and a0.

at this point

U = 0

v0 = u + a0*t

v0 = 0 + a0*t

v0 = a0*t

t2 = v0/a0

C)

The train does not stop at the stoplight. How far behind the train is the car when the car reaches its original speed v0 again? Express the separation distance in terms of v0 and a0 . Your answer should be positive.

t1 = t2 = t

Distance covered by the train = v0 (2t) = 2v0t

and we know t = v0/a0

so distanced covered = 2v0 (v0/a0) = (2v0^2)/a0

now distance covered by car before coming to full stop

Vf2 = v0^2- 2a0s1

2a0s1 = v0^2

s1 = v0^2 / 2a0

After the full stop;

V0^2 = 2a0s2

s2 = v0^2/2a0

Snet = 2v0^2 /2a0 = v0^2/a0

Now the separation between train and car

= (2v0^2)/a0 - v0^2/a0

= v0^2/a0

8 0
4 years ago
If a car increases its velocity from 1m/s to 3.6km/hr in 5 seconds what’s its acceleration
EleoNora [17]

Answer:

applying 1st eq of motion vf=vi+at here we have to find a=vf-vi/t , a= 1-1/5 , a=0/5 then we got a=0 here(vf value 3.6km/h is converted in standard unit 3.6×1000/3600 so we get vf=1m/s²

7 0
3 years ago
A person is listening with his ear against the rail for an oncoming train. When the train is 1.65 km away, how long will it take
Vitek1552 [10]

Answer:

Time = 0.317 seconds.

Explanation:

Given the following data;

Distance = 1.65km to meters = 1.65 * 1000 = 1650 meters

We know that the speed of sound in steel is equal to 5200m/s

To find the time to hear the sound of the whistle;

Time = distance/speed

Substituting into the equation, we have

Time = 1650/5200

Time = 0.317 seconds.

Therefore, it will take him 0.317 seconds to hear the sound of the whistle.

3 0
3 years ago
Positive ions differ from neutral atoms in that
Katena32 [7]

Answer:

The answer is C.

Explanation:

An ion is unlike a neutral atom in the fact that it has a charge. Because electrons are negatively charged, an atom becomes more positive if electrons are lost.

5 0
3 years ago
On earth a 2.25 kg object is lifted a height of 5.22m. What is the gravitational potential energy
zysi [14]

Answer:

<h2>117.45 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

GPE = 2.25 × 10 × 5.22

We have the final answer as

<h3>117.45 J</h3>

Hope this helps you

8 0
3 years ago
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