Find the molar mass of Fe_2O_3
2Fe = 2*56 = 112
3O = 3* 16 = 48
Molar Mass = 160 grams
moles= given mass / molar mass
moles = 28 / 160
moles = 0.175 <<<< answer
Answer:
D, when there is a large antelope population
Explanation:
I took the k12 test and got it right
Answer:
c) 0.10M NaCl
Explanation:
<em>Options are:</em>
<em>a) 0.20M NaCl</em>
<em>b) Very acidic</em>
<em>c) 0.10M NaCl</em>
<em>d) 0.10M HCl + 0.20M NaOH</em>
<em>e) Slightly acidic.</em>
<em />
Based on the reaction:
NaOH + HCl → H₂O + NaCl
You can see than 1 mole of NaOH reacts per mole of HCl producing 1 mole of NaCl
Assuming 1L of 0.20M HCl reacts with 1L of NaOH, moles of both compounds are:
1L * 0.20mol/L = 0.20 moles reacts. That means moles of NaCl produced are 0.20moles in 2L. Molarity of NaCl is:
0.20mol / 2L = 0.10M NaCl
That means, right option is:
<h3>c) 0.10M NaCl</h3>
the equation is CH4 + O2 --> H20 + CO2.
im pretty sure it absorbs the heat.
Answer:- No, the company would not be able to full fill the order.
Solution:- The balanced equation for the formation of ammonia by the reaction of hydrogen with nitrogen is:

We have been given with 22000 grams of nitrogen and 1000 grams of hydrogen. Let's convert grams of each to moles:
moles of nitrogen = 
moles of nitrogen = 785.71 mol
moles of hydrogen = 
moles of hydrogen = 500 mol
From balanced equation 3 moles of hydrogen react with 1 mol of nitrogen. Let's calculate how many moles of nitrogen would react with 500 mol of hydrogen:

= 
166.67 moles of nitrogen are required and 785.71 moles of it are available. It means nitrogen is in excess and hydrogen is limiting. Product yield depends on limiting reactant. So, let's calculate the amount of ammonia formed from moles of hydrogen as:

= 5666.67g of ammonia
let's convert the grams of ammonia to number of batches as:

= 32 batches
Company needs to make 70 batches of ammonia but from given amounts of hydrogen and nitrogen only 32 batches could be made. It means the company would not be able to full fill the order.