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dezoksy [38]
3 years ago
12

An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to -5°C. Assume that there is no volume change in t

he tire.
What is the new pressure of the tire after the temperature change?
Chemistry
1 answer:
dmitriy555 [2]3 years ago
7 0

Answer:

P₂ = 2.7 atm

Explanation:

Given data:

Initial temperature = 30°C

Initial pressure = 3.00 atm

Final temperature = -5°C

Final pressure = ?

Solution:

Initial temperature = 30°C = 30 + 273 = 303 K

Final temperature = -5°C = -5 + 273 = 268 K

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

3.0 atm / 303 K = P₂/268 K

P₂ = 3.0 atm × 268 K / 303 K

P₂ = 804 atm. K /293 K

P₂ = 2.7 atm

You might be interested in
Find the mass of an object on earth if its weight is 100N
Kaylis [27]

Answer:

0.19 kg

8 N

1.964 N

58.86 N

15 kg

Explanation:

w = Weight of an object = 100 N

g = Acceleration due to gravity of Earth = 9.81\ \text{m/s}^2

m = Mass of an object

Weight is given by

w=mg\\\Rightarrow m=\dfrac{w}{g}\\\Rightarrow m=\dfrac{100}{9.81}\\\Rightarrow m=10.19\ \text{kg}

Mass of the object is 0.19 kg

g = 2\ \text{m/s}^2

m = 4 kg

w=mg\\\Rightarrow w=4\times 2\\\Rightarrow w=8\ \text{N}

Weight of the object is 8 N.

m = 200 g

w=mg\\\Rightarrow w=0.2\times 9.81\\\Rightarrow w=1.964\ \text{N}

Weight of the object is 1.964 N.

Weight is the force the Earth exerts on an object which is on the surface of the Earth.

m = 6kg

w=mg\\\Rightarrow w=6\times 9.81\\\Rightarrow w=58.86\ \text{N}

The force of the object is 58.86 N.

w = 150 N

a = g = 10\ \text{m/s}^2

m=\dfrac{w}{g}\\\Rightarrow m=\dfrac{150}{10}\\\Rightarrow m=15\ \text{kg}

Mass of the object is 15 kg.

7 0
3 years ago
問上面照片的題目,何者不是構成蛋白質的主要成分原素?
maxonik [38]
What does this even say
8 0
3 years ago
Please give me the answer please
zepelin [54]

Answer:

A. 30cm³

Explanation:

Based on the chemical reaction:

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

<em>1 mol of calcium carbonate reacts with 2 moles of HCl to produce 1 mol of CO₂</em>

<em />

To solve this question we must convert the mass of each reactant to moles. With the moles we can find limiting reactant and the moles of CO₂ produced. Using PV = nRT we can find the volume of the gas:

<em>Moles CaCO₃ -Molar mass: 100.09g/mol-</em>

1.00g * (1mol / 100.09g) = 9.991x10⁻³ moles

<em>Moles HCl:</em>

50cm³ = 0.0500dm³ * (0.05 mol / dm³) = 2.5x10⁻³ moles

For a complete reaction of 2.5x10⁻³ moles HCl there are necessaries:

2.5x10⁻³ moles HCl * (1mol CaCO₃ / 2mol HCl) = 1.25x10⁻³ moles CaCO₃. As there are 9.991x10⁻³ moles, HCl is limiting reactant.

The moles produced of CO₂ are:

2.5x10⁻³ moles HCl * (1mol CO₂ / 2mol HCl) = 1.25x10⁻³ moles CO₂

Using PV = nRT

<em>Where P is pressure = 1atm assuming STP</em>

<em>V volume in L</em>

<em>n moles = 1.25x10⁻³ moles CO₂</em>

<em>R gas constant = 0.082atmL/molK</em>

<em>T = 273.15K at STP</em>

<em />

V = nRT / P

1.25x10⁻³ moles * 0.082atmL/molK*273.15K / 1atm = V

0.028L = V

28cm³ = V

As 28cm³ ≈ 30cm³

Right option is:

<h3>A. 30cm³</h3>

5 0
3 years ago
1. When two atoms with different electronegativities are bonded together, a bond dipole exists. These are displayed with an arro
Natali5045456 [20]

Answer:

In order: LOWER, HIGHER, NEGATIVE, POSITIVE, INCREASE

Explanation:

First you must consider the definition of electronegativity.

All in all, electronegativity is the ability of an atom to attract electrons to itself. For this explanation, let's just consider the groups 1, 2, 13-17, and the noble gases of the periodic table. Furthermore, let's also consider the octet rule. The octet rule says that the last orbit of an atom tends to have 8 electrons in order to be stable.

If you take an atom like Sodium (Na) and search its distribution of electrons by levels, you'll see these number in the last two orbits: 8.1

The penultimate orbit has 8 electrons and the last one has only 1. Therefore, in order to futfill the octet rule what do you think it's easier? Losing the last electron and leaving the 8 electrones of the penultimate orbit as last orbit? Or maybe taking 7 electrons for the last orbit and, hence, futfilling the octet? Well, the answer is the first case.

The more you move from group to group (i.e, rightwards in the periodic table), more electrons will have in their last orbit.

So, in order to respond your question: Yes you should display it like this:

A --> B

Consider A and B two random atoms, for which B's electronegativity is higher than A's. This arrow shows the tendency of the electron flow.

As electrons go to the more electronegative atom, the whole electronic ''cloud'' will tend to be closer to B, because this atom is more electronegative. Hence, there will be a partial (not fixed) negative charge on B rather than on A. This is due to B's high electronegativity. This means that the negative charge will spend more time on B rather than on A, this is what partial negative charge means.

The higher the electronegativity is, the higher the magnitudes of the partial charges --> Therefore, these partial charges are increased and sometimes it might lead to the chemical bond breakage.

8 0
3 years ago
Neutrons have. a.negative b.positive c.no charge d.nucleus
Firdavs [7]
A negative That's the answer
5 0
3 years ago
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