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dezoksy [38]
3 years ago
12

An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to -5°C. Assume that there is no volume change in t

he tire.
What is the new pressure of the tire after the temperature change?
Chemistry
1 answer:
dmitriy555 [2]3 years ago
7 0

Answer:

P₂ = 2.7 atm

Explanation:

Given data:

Initial temperature = 30°C

Initial pressure = 3.00 atm

Final temperature = -5°C

Final pressure = ?

Solution:

Initial temperature = 30°C = 30 + 273 = 303 K

Final temperature = -5°C = -5 + 273 = 268 K

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

3.0 atm / 303 K = P₂/268 K

P₂ = 3.0 atm × 268 K / 303 K

P₂ = 804 atm. K /293 K

P₂ = 2.7 atm

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Answer:

d = 0.98 g/L

Explanation:

Given data:

Density of acetylene = ?

Pressure = 0.910 atm

Temperature = 20°C (20+273 = 293 K)

Solution:

Formula:

PM = dRT

R = general gas constant = 0.0821 atm.L/mol.K

M = molecular mass = 26.04 g/mol

0.910 atm × 26.04 g/mol = d × 0.0821 atm.L/mol.K×293 K

23.7  atm.g/mol = d × 24.1 atm.L/mol

d = 23.7  atm.g/mol / 24.1 atm.L/mol

d = 0.98 g/L

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It has been assumed that the intimate coating layer generated on the positive electrode, known as cathode electrolyte interphase (CEI), is crucial. However, there are still numerous questions about CEI. This results from the absence of useful instruments to evaluate the chemical and structural characteristics of these delicate interphases at the nanoscale. Here, using cryogenic electron microscopy, we establish a methodology to maintain the natural condition and directly see the interface on the positive electrode.

Learn more about Cathode electrolyte interphase here:

brainly.com/question/861659

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Explanation:

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