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IRISSAK [1]
3 years ago
14

What is a precipitate?

Chemistry
2 answers:
zloy xaker [14]3 years ago
8 0

Answer:

Hi there!

A precipitate is the <u>creation</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>solid</u> from a chemical reaction of <u>liquids</u>

Hope this helps!

qwelly [4]3 years ago
8 0

Answer:

it's a cause(an event or situation, typically one that's is bad or undesirable) to happen suddenly, unexpected, or prematurely.

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Which of the following lists elements from lowest to highest atomic number
vitfil [10]
Lowest is Hydrogen highest is <span>Beryllium
-HOPE THIS HELPED </span>
8 0
3 years ago
H-1
bonufazy [111]
Answer = B = Neutrons and Mass Number

Isotopes 
are defined as those atoms which have same atomic number but different atomic masses.

Atomic mass is basically the number of protons and neutrons present in an atom.

Atomic number is the number of protons present in an atom.

So, in isotopes the number of protons are same but the number of neutrons vary due to which atomic masses also vary.
In given three isotopes, all have same number of protons but different number of neutrons.
i.e.
H-1 = 1 P + 0 N = 1 u (Proton)
H-2 = 1 P + 1 N = 2 u (Deuterium)
H-3 = 1 P + 2 N = 3 u (Tritium)

Hence, it is clear that the number after H shows a change in number of neutrons and mass number.

7 0
3 years ago
Read 2 more answers
What is the molar mass of a compound?
Masteriza [31]

Answer:

The molar mass of a compound is The mass in grams of 1 mole of the compound (Option A)

Explanation:

Let's take ammonia as an example (NH3)

Mass of N = 14 g

Mass of H = 1 g

Molar mass of ammonia is Mass of N + (Mass of H).3

14 + 3 = 17 g/m

Ammonia is a compound that has 1 mol of N, plus 3 moles of H (see the formula)

The number of atoms in 1 mole of the compound --> This is Avogadro

7 0
2 years ago
What is the molar mass of fluorine gas, F2?
Paladinen [302]

Answer:

37.99681 g/mol

Explanation:

Hope it helps!

6 0
3 years ago
Read 2 more answers
The conversion of cyclopropane to propene occurs with a first-order rate constant of . How long will it take for the concentrati
Gennadij [26K]

This is an incomplete question, here is a complete question.

The conversion of cyclopropane to propene occurs with a first-order rate constant of 2.42 × 10⁻² hr⁻¹. How long will it take for the concentration of cyclopropane to decrease from an initial concentration 0.080 mol/L to 0.053 mol/L?

Answer : The time taken will be, 17.0 hr

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 2.42\times 10^{-2}\text{ hr}^{-1}

t = time passed by the sample  = ?

a = initial concentration of the reactant  = 0.080 M

a - x = concentration left = 0.053 M

Now put all the given values in above equation, we get

t=\frac{2.303}{2.42\times 10^{-2}}\log\frac{0.080}{0.053}

t=17.0\text{ hr}

Therefore, the time taken will be, 17.0 hr

5 0
3 years ago
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