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kotykmax [81]
3 years ago
13

Your family loves turkey! Uncle Bill ate 1/4 of the turkey, cousin Chris ate 15% of the turkey, cousin Timmy ate 0.3 of the turk

ey and little Dave ate 12% of the turkey. Who ate the most turkey?
What fraction (or decimal, or percent) of the turkey was eaten?

Show your work here:



Defend your answer in writing:
Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0
(1 / 4) = .25
.25 * 100% = 25%
Uncle Bill ate 25%
Cousin Chris ate 15%
.3 * 100% = 30%
Cousin Timmy ate 30%
Little Dave ate 12%
You ate none.

Cousin Timmy ate the most, 18% of the turkey is left, and 82% of the turkey was eaten.


Defend my work in writing:

I converted my fractions and decimals to percents to find the different percents eaten for each person.
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Solve using quadratic formula<br> 1. y=3x^2-x-6<br><br> 2. y=-5x+7x+3
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My estimated answer for 1 is x=1.59 or x=-1.26 and my exact answer is (in word form) x= 1 plus or minus the square root of 73 over 6. my estimated answer for 2 is x=-0.34 or x=1.74 and my exact answer (in word form) is x= -7 plus or minus the square root of 109 over -10. I took a picture of my work and hopefully you can read it

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The Honda Accord was named the best midsized car for resale value for by the Kelley Blue Book (Kelley Blue Book website). The fi
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The Honda Accord was named the best midsized car for resale value for by the Kelley Blue Book (Kelley Blue Book website). The file AutoResale contains mileage, age, and selling price for a sample of 33 Honda Accords. Click on the datafile logo to reference the data. The estimated regression equation is Selling price = 20385.25049 - 0.03739 Mileage - 686.33668 age. Round your answers to the nearest dollar. a. Estimate the selling price of a four-year-old Honda Accord with mileage of 40,000 miles.

answer :  ≈ $16144

Step-by-step explanation:

<u>Determine the selling price of a four-year-old Honda Accord with mileage of </u><u>40,000</u><u> miles.</u>

Given data :

Age= 4 year, Mileage=40,000 miles

Hence the selling price

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4 0
3 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

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Answer:

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Step-by-step explanation:

Hey there!

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Hope this helps!

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