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77julia77 [94]
3 years ago
5

What force is required to accelerate a body with a mass of 15kilograms at a rate of

Physics
1 answer:
Paladinen [302]3 years ago
4 0

The force required is

                     (15 kg) x (the acceleration, in m/s²)          newtons.

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How much work is done by 0.070 m3 of gas, when the volume remains constant with pressure of 63 x 105 Pa?
ICE Princess25 [194]

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

W = P\Delta V

where,

W = Work done by the gas

P = Pressure of the gas

ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

W = P(0\ m^3)\\

<u>W = 0 J</u>

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3 years ago
According to the photon energy formula, tripling the frequency of the radiation from a monochromatic source will change the ener
Harrizon [31]

Answer:

By a factor of 3

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4 years ago
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In a thin film experiment, a wedge of air is used between two glass plates. If the wavelength of the incident light in air is 48
cluponka [151]

Answer:

The thickness is  \Delta y =  2.4 *10^{-6} \  m

Explanation:

From the question we are told that

   The wavelength is  \lambda  = 480 \ nm = 480*10^{-9} \  m

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Generally the condition for destructive interference is mathematically represented as

        y = \frac{m \lambda}{2}

Here y is the path difference between the central maxima(i.e the origin) and any dark fringe

So  the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as

      y_1 - y_2 = \Delta y =  \frac{m_1 \lambda}{2} -  \frac{m_2 \lambda}{2}

=>  y_1 - y_2 = \Delta y =  \frac{16 *480*10^{-9}}{2} -  \frac{6 *480*10^{-9}}{2}

=>  y_1 - y_2 = \Delta y =  5 (480*10^{-9})

=>  \Delta y =  2.4 *10^{-6} \  m

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Korolek [52]
Your lungs aren’t the ones that make the sound
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3 years ago
How to round numbers and find significant digits in physics?? <br> Simple answer? Please???
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Answer:

Heya how have you been doing

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