Question

A bungee jumper of mass m = 65 kg jumps from a bridge.

Answer 1

To solve the problem it is necessary to apply energy conservation.

By definition we know that kinetic energy is equal to potential energy, therefore

PE = KE

$mgh = \frac{1}{2}mv^2$

Where,

m = mass

g = gravitaty constat

v = velocity

h = height

Re-arrange to find h,

$h=\frac{v^2}{2g}$

Replacing with our values

$h=\frac{26^2}{2*9.8}$

$h = 34.498\approx 34.5m$

Therefore the correct answer is C.