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Leviafan [203]
3 years ago
8

A bungee jumper of mass m = 65 kg jumps from a bridge.

Physics
1 answer:
yawa3891 [41]3 years ago
3 0

To solve the problem it is necessary to apply energy conservation.

By definition we know that kinetic energy is equal to potential energy, therefore

PE = KE

mgh = \frac{1}{2}mv^2

Where,

m = mass

g = gravitaty constat

v = velocity

h = height

Re-arrange to find h,

h=\frac{v^2}{2g}

Replacing with our values

h=\frac{26^2}{2*9.8}

h = 34.498\approx 34.5m

Therefore the correct answer is C.

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A box of mass m = 1.80 kg is dropped from rest onto a massless, vertical spring with spring constant k = 2.00 ✕ 102 N/m that is
Rudik [331]

Answer:

spring compressed is 0.724 m

Explanation:

given data

mass = 1.80 kg

spring constant k = 2 × 10²  N/m

initial height = 2.25 m

solution

we know from conservation of energy is

mg(h+x)  = 0.5 × k × x²       ...................1

here x is compression in spring

so put here value in equation 1 we get

1.8 × 9.8 × (2.25+x)  = 0.5 × 2× 10² × x²

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