A)
5m/s^2
(12m/s-2m/s)
__________ = 5m/s^2
2s
To develop this problem it is necessary to use the equations of description of the simple harmonic movement in which the acceleration and angular velocity are expressed as a function of the Amplitude.
Our values are given as


The angular velocity of a body can be described as a function of frequency as



PART A) The expression for the maximum angular velocity is given by the amplitude so that



PART B) The maximum acceleration on your part would be given by the expression



Question: How fast was the arrow moving before it joined the block?
Answer:
The arrow was moving at 15.9 m/s.
Explanation:
The law of conservation of energy says that the kinetic energy of the arrow must be converted into the potential energy of the block and arrow after it they join:

where
is the mass of the arrow,
is the mass of the block,
of the change in height of the block after the collision, and
is the velocity of the arrow before it hit the block.
Solving for the velocity
, we get:

and we put in the numerical values
,



and simplify to get:

The arrow was moving at 15.9 m/s
Answer:
True
Explanation:
when the object is larger , the inertia of the object is larger so its tendency to change its state of motion is reduced is reduced.
Explanation:
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