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forsale [732]
3 years ago
9

Una carga eléctrica de 120 Coulomb pasa uniformemente por la sección transversal de un hilo conductor durante un minuto. La inte

nsidad de la corriente eléctrica que circula en ese conductor es
Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

   I = 2 A

Explanation:

Electric current is defined as the amount of face per unit of time

         I = Q / t

where Q is the charge and t is the time

let's reduce the time to the SI system

         t = 1 min (60s / 1 min) = 60 s

let's calculate

         I = 120/60

         I = 2 A

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Calculate the acceleration of a galloping horse going from 2 m/s to 12 m/s in 2 seconds.
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A)
5m/s^2


(12m/s-2m/s)
__________ = 5m/s^2
2s
8 0
3 years ago
Atoms in a solid are not stationary, but vibrate about their equilibrium positions. Typically, the frequency of vibration is abo
hoa [83]

To develop this problem it is necessary to use the equations of description of the simple harmonic movement in which the acceleration and angular velocity are expressed as a function of the Amplitude.

Our values are given as

f = 4.11 *10^{12} Hz

A = 1.23 * 10^{-11}m

The angular velocity of a body can be described as a function of frequency as

\omega = 2\pi f

\omega = 2\pi 4.11 *10^{12}

\omega=2.582*10^{13} rad/s

PART A) The expression for the maximum angular velocity is given by the amplitude so that

V = A\omega

V =( 1.23 * 10^{-11})(2.582*10^{13})

V =  = 317.586m/s

PART B) The maximum acceleration on your part would be given by the expression

a = A \omega^2

a =( 1.23 * 10^{-11})(2.582*10^{13})^2

a= 8.2*10^{15}m/s^2

4 0
3 years ago
The 45-g arrow is launched so that it hits and embeds in a 1.40 kg block. The block hangs from strings. After the arrow joins th
worty [1.4K]

Question: How fast was the arrow moving before it joined the block?

Answer:

The arrow was moving at 15.9 m/s.

Explanation:

The law of conservation of energy says that the kinetic energy of the arrow must be converted into the potential energy of the block and arrow after it they join:

\dfrac{1}{2}m_av^2 = (m_b+m_a)\Delta Hg

where m_a is the mass of the arrow, m_b is the mass of the block, \Delta H of the change in height of the block after the collision, and v is the velocity of the arrow before it hit the block.

Solving for the velocity v, we get:

$v = \sqrt{\frac{2(m_b+m_a)\Delta Hg}{m_a} } $

and we put in the numerical values

m_a = 0.045kg,

m_b = 1.40kg,

\Delta H = 0.4m,

g= 9.8m/s^2

and simplify to get:

\boxed{ v= 15.9m/s}

The arrow was moving at 15.9 m/s

6 0
3 years ago
Question:The greater the
Romashka-Z-Leto [24]

Answer:

True

Explanation:

when the object is larger , the inertia of the object is larger so its tendency to change its state of motion is reduced is reduced.

5 0
3 years ago
I need help on this question!
Mashutka [201]

Explanation:

click the link you can get answer of the question

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3 years ago
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