First, find the missing leg of ΔBCD (line BD). Using the Pythagorean Theorem, subtract (5^2)-(3^2) [25-9], and you get 16. Find the square root of 16, and you get <em>4</em> for line BD. Now, you can find AB. Add (7^2)+(4^2) [49+16], and you get 65. Now, since 65 isn't a perfect root, just use √(65)
Answer: Line AB equals √(65).
I think boys =18
girls=12
boys :x
girls:y
student:z
the number of group for the boys :n
the numberof group for the girls :m
so x=(3/5)*z
y=(2/5)* z
x/y=3/2
3y-2x=0
(1/10)*z*n=(3/5) *z
so n=6
(1/5)*z*m=(2/5)* z
put x=(1/10)*z*6
y=(1/5)*z*2
into 3y-2x=0 and z=30
z=30 so x=(1/10)*30*6=18
y=(1/5)*30*2=12
to inverse a equation make all y's x and andy x's y
Thus the inverse is
x=4y-8
Evaluated to
4y=x+8
y= \frac{1}{4}x +2
Answer: 2.2x * 10^3
You would have to move the decimal place 3 times for 2.2x to get 2,200x, thus you get 10^3.
Hope this helps!
