Answer:

Step-by-step explanation:
We know that
sin²x+cos²x=1
so
clear cos x
cos x=(+/-)√[1-sin²x]
in this problem
<span>Angle 0 is in quadrant 1 -----> cos o and sin o are positive
</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5
the answer is
cos o=√21/5
Your answer is c, an obtuse triangle because if the two side lengths are the same length along with a longer side, it become obtuse
let me know if you have any other questions
:)
Answer:
the height of the flagpole is 5 meters
Step-by-step explanation:
The computation of the height of the flagpole is given below
Given that
the length of the rope is 13 meters
And, the ground would be 12 meters
Based on the above information, the height of the flagpole is
= √13^2 - √12^2
= √169 - √144
= √25
= 5 meters
hence the height of the flagpole is 5 meters
<h3>
Answer: -10 and -40</h3>
===============================================================
Explanation:
a = 200 = first term
d = -30 = common difference
Tn = nth term
Tn = a + d(n-1)
Tn = 200 + (-30)(n-1)
Tn = 200 - 30n + 30
Tn = -30n + 230
Set Tn less than 0 and isolate n
Tn < 0
-30n + 230 < 0
230 < 30n
30n > 230
n > 230/30
n > 7.667 approximately
Rounding up to the nearest whole number gets us 
So Tn starts to turn negative when n = 8
We can see that,
Tn = -30n + 230
T7 = -30*7 + 230
T7 = 20
and
Tn = -30n + 230
T8 = -30*8 + 230
T8 = -10 is the 8th term
and lastly
Tn = -30n + 230
T9 = -30*9 + 230
T9 = -40 is the ninth term
Or once you determine that T7 = 20, you subtract 30 from it to get 20-30 = -10 which is the value of T8. Then T9 = -40 because -10-30 = -40.