Answer:
34.9 mL
Explanation:
First we <u>convert 23.6 g of LiBr into moles</u>, using its <em>molar mass </em>(86.845 g/mol):
- 23.6 g ÷ 86.845 g/mol = 0.272 mol LiBr
Now we can <u>calculate the required volume</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- liters = moles / Molarity
- 0.272 mol / 7.8 M = 0.0349 L
We can <u>convert L into mL</u>:
- 0.0348 L * 1000 = 34.9 mL
Answer:
The answer to your question is 23.4 moles of Glucose
Explanation:
Data
moles of Oxygen = ?
moles of glucose = 3.9
-Balanced chemical reaction
1C₆H₁₂O₆ + 6O₂ ⇒ 6H₂O + 6CO₂
Process
1.- To solve this problem, use the coefficient of the balanced chemical equation, and use proportions and cross multiplication.
1 mol of C₆H₁₂O₆ -------------------- 6 moles of O₂
3.9 moles of C₆H₁₂O₆ ------------------ x
x = (3.9 x 6 ) / 1
x = 23.4 moles
2.- Conclusion
3.9 moles of glucose consume 23.4 moles of oxygen
B all of these will increase the strength of the magnet
There are 0.000076 moles in 4.6 x 10^19 atoms.
