Answer:
A mixture whose components are soluble in each other. ... a solution that has water as its solvent; most have an ionic substance as the solute, may contain a liquid ... The suspensions of particles larger than individual ions or molecules, but the ... This effect is used to determine whether a mixture is a true solution or a colloid.
process of solute particles being surrounded by water molecules arranged in a ... solution. homogeneous mixture consisting of a solute dissolved into a solvent. ... apart from the crystal, the individual ions are then surrounded by solvent particles in a ... are intermediate in size between those of a solution and a suspension.
A suspension is a heterogeneous mixture in which some of the particles ... The particles in a suspension are far larger than those of a solution, so gravity is … ... Particle size: 0.01-1nm; atoms, ions or molecules, Particle size: ... solutions because the individual dispersed particles of a colloid cannot be seen.
Explanation:
Plants and wetlands purify water by acting as filter media. The roots of the plants and the wetlands would trap pollutants like sediments and hold onto the. In wetlands, the flow of water is slow allowing for the sediments to settle due to gravity onto the bottom where the plants would accumulate them into place. With this, excess nutrients would be remove and will prevent polluting bodies of water. Also, bacteria like E. coli and Salmonella can be filtered out from the water. There are plants that works excellent for filtering out pollutants like the lilies, hornwort, bulrushes and rushes.
Answer:
Answer is explained in the explanation section below.
Explanation:
Solution:
Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.
a) We need to find the major species from A to F.
Major Species at A:
1. 
Major Species at B:
1.
2. 
Major Species at C:
1.
Major Species at D:
1.
2. 
Major Species at E:
1.
Major Species at F:
1.
b) pH calculation:
At Halfway point B:
pH = pK
+ log[
]/[H
]
pH = pK = 6.35
Similarly, at halfway point D.
At point D,
pH = pK
+ log [H]/[H2]
pH = pK = 10.33
Answer:
131 atm
Explanation:
To find the new pressure, you need to use Boyle's Law:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.
P₁ = 3.88 atm P₂ = ? atm
V₁ = 7.74 L V₂ = 0.23 L
P₁V₁ = P₂V₂ <----- Boyle's Law
(3.88 atm)(7.74 L) = P₂(0.23 L) <----- Insert values
30.0312 = P₂(0.23 L) <----- Simplify left side
131 = P₂ <----- Divide both sides by 0.23
D snails, guppies and plants. The community should be diverse and have lots of biodiversity.
