Answer:
M₂ = 0.9 M
Explanation:
Given data:
Initial Volume = V₁ = 250 mL
Initial molarity = M₁= 3 M
Final volume = 850 mL
Final molarity = ?
Solution:
M₁V₁ = M₂V₂
M₂ = M₁V₁ /V₂
M₂ = 3 M × 250 mL / 850 mL
M₂ = 750 M / 850
M₂ = 0.9 M
The solution for this problem is:
Look for the moles of NaOH which is 0.0385 L x 0.150 M = 0.00578
H3PO4 + 3 NaOH = Na3PO4 + 3 H2O
moles H3PO4 = 0.00578 / 3 = 0.00193
M of H3PO4 = 0.00193 mol / 0.0150 L= 0.128 is the molality we are looking for in this problem.
Answer:
1,144 grams
Explanation:
Mass = Density * Volume
220mL * 5.2 g/mL = 1,144 grams
The most likely answer is the boiling point and freezing point of water. The Celsius scale starts at the freezing point of water (0°C) and than scaled so that 100°C fell on the boiling point of water.
I hope this helps. Let me know if anything is unclear.