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Answer:
a) Theoretical yield of ethanol = 34.778 g
b) % yield of ethanol = 37.38%
Explanation:
a)
C6H12O6 → 2 C2H5OH + 2 CO2
Molar mass of glucose = 180.156 g/mol
Molar mass of ethanol = 46.07 g/mol
amount of glucose taken = 68.0 g
No. of mole = Amount of substance in g/Molar mass
[text]No. of mole = \frac{68.0\;}{180.156\; g/mol} =0.37745 mol[\text]
from reaction stoichiometry, one mole of glucose fermented two form 2 mole of ethanol.
therefore, 0.37745 mol of glucose will form 0.37745*2 moles of ethanol.
No. of moles of ethanol formed = 0.7549 mol
theoretical yield of ethanol = 0.7549 x 46.07 = 34.778 g
b)
Actual yield = 13.0 g
Theoretical yield = 34.778 g
= 37.38%