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Over [174]
4 years ago
10

Which of the following has no energy?

Physics
2 answers:
tankabanditka [31]4 years ago
7 0
D. is correct because a wrecking ball has potential energy.
Readme [11.4K]4 years ago
4 0
The correct answer is D: which is none of the above.
Hint: a wreckling ball contains pontential energy that acts like a pendulum

a pot of water contains pontential thermal energy
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Which of the following atoms is least likely to form chemical bonds with other atoms
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The atom that would least likely form chemical bonds with other atoms would be C. A neon containing 4 valence electrons, this is because neon itself is an inert gas, it would not necessarily react as it already possess the maximum number of electrons needed to achieve stability and have a full octet, even if it is forced to obtain 4 valence electrons it would not react with other atoms.
8 0
3 years ago
What is the volume of an object with a mass of 15 grams and a density<br> of 2 g/ml
OleMash [197]

Answer: 7.5 ml

Explanation: Density= mass/ volume.

So, volume = mass / density

                    = 15g / 2 g/ml

                    = 7.5 ml

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3 years ago
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3 years ago
A storage tank holds methane at 120 K, with a quality of 25 %, and it warms up by 5°C per hour due to a failure in the refrigera
lord [1]

One of the fundamental pillars to solve this problem is the use of thermodynamic tables to be able to find the values of the specific volume of saturated liquid and evaporation. We will be guided by the table B.7.1 'Saturated Methane' from which we will obtain the properties of this gas at the given temperature. Later considering the isobaric process we will calculate with that volume the properties in state two. Finally we will calculate the times through the differences of the temperatures and reasons of change of heat.

Table B.7.1: Saturated Methane

T_1 = 120K

p_1 = 191.6kPa

v_f = 0.002439m^3/kg

v_{fg} = 0.30367 m^3/kg

Calculate the specific volume of the methane at state 1

v_1 = v_f+x_1v_{fg}

v_1 = 0.002439+ (0.25)(0.30367)

v_1 = 0.0783m^3/kg

Assume the tank is rigid, specific volume remains constant

v_2 = v_1

v_2 = 0.0783m^3/kg

Now from the same table we can obtain the properties,

At v_g = 0.0783m^3/kg

T_2 = 145K

p_2 = 823.7kPa

We can calculate the time taken for the methane to become a single phase

t = \frac{T_2-T_1}{\dot{T}}

Here

T_1 = Initial temperature of Methane

\dot{T} = Warming rate

Replacing

t = \frac{(145-273)-(120-273)}{5}

t = \frac{25}{5}

t = 5hr

Therefore the time taken for the methane to become a single phase is 5hr

5 0
3 years ago
Rank the vector combinations on the basis of their magnitude.
melomori [17]

I think this is about the 5th or 6th time I've seen this question
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6 0
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