Answer:
the stove energy went into heating water is 837.2 kJ.
Explanation:
given,
mass of water = 2000 grams
initial temperature = 0° C
Final temperature = 100° C
specific heat of water (c) = 4.186 joule/gram
energy = m c Δ T
= 2000 × 4.186 × (100° - 0°)
= 837200 J
= 837.2 kJ
hence, the stove energy went into heating water is 837.2 kJ.
Answer: The most likely identity of the substance is iron.
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q = Heat absorbed=
Joules
m= mass of substance = 11.9 g
c = specific heat capacity = ?
Initial temperature of the water =
= 25.0°C
Final temperature of the water =
= 45.0°CChange in temperature ,
Putting in the values, we get:


The specific heat of 0.45 is for iron and thus the substance is iron.
50% of the moon is always illuminated, however during it's quarter phase means that we only see a quarter of what's really lit up. So it LOOKS like the moon is only 25% lit and 75% dark, it's truly 50/50. We only see that 25% since we can see it from one angle.
The answer is A.
Sy = 1650 x sin30.5 = 837.4 m toward south
Sx = 1650 x cos30.5 = 1421.7 m toward east