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AfilCa [17]
2 years ago
6

What would you expect to cause a drop in air pressure?

Physics
2 answers:
givi [52]2 years ago
7 0
D. The air temperature staying the same
Murrr4er [49]2 years ago
6 0

Answer:

D

Explanation:

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Hatshy [7]

Answer:

Good morning. Whats about you

4 0
3 years ago
Read 2 more answers
Yvonne has gained a reputation for her cheesecakes. She takes orders for 10 cheesecakes and spends 8.5 hours on one Saturday bak
VLD [36.1K]
A) 10÷8.5
b) 120÷10
c) answer A÷Answer B.

sure on first two, not so sure on C.
3 0
3 years ago
A satellite at a particular point along an elliptical orbit has a gravitational potential energy of 4700 MJ with respect to Eart
erastovalidia [21]

during satellite motion we know that total energy is always conserved

so here we will have

KE_i + PE_i = KE_f + PE_f

here we know that

KE_i = 4800 MJ

PE_i = 4700 MJ

now at other position

PE_f = 6000 MJ

now from above equation we have

4800 +4700 = 6000 + KE

now we have

9500 = 6000 + KE

KE = 9500 - 6000 = 3500 MJ

so its kinetic energy will be 3500 MJ

6 0
3 years ago
B.A certain piece of copper wire is determined to have a mass of 2.00 g per meter.
masha68 [24]

Answer:

14cm

Explanation:

Mass per gram of the piece of wire;

         2g of the wire is found in 1m

 Since

       100cm  = 1m;

 

So;

       100cm of the wire contains 2g of the wire

To provide 0.28g

 Since;

        2g of wire is made up of 100cm

      0.28g of wire will be contained in \frac{100 x 0.28}{2}   = 14cm

14cm of the wire will contain 0.28g

8 0
3 years ago
Two cylinders A&B at the same temperature contains the same quantity of the same kind of gas. Cylinder A has three times the
GREYUIT [131]

Answer:

pressure in cylinder A must be one third of pressure in cylinder B

Explanation:

We are told that the temperature and quantity of the gases in the 2 cylinders are same.

Thus, number of moles and temperature will be the same for both cylinders.

To this effect we will use the formula for ideal gas equation which is;

PV = nRT

Where;

P is prrssure

V is volume

n is number of moles

T is temperature

R is gas constant

We are told that Cylinder A has three times the volume of cylinder .

Thus;

V_a = 3V_b

For cylinder A;

Pressure = P_a

Volume = 3V_b

Number of moles = n

Thus;

P_a × 3V_b = nRT

For cylinder B;

Pressure = P_b

Volume = V_b

Number of moles = n

Thus,

P_b × V_b = nRT

Combining the equations for both cylinders, we have;

P_a × 3V_b = P_b × V_b

V_b will cancel out to give;

3P_a = P_b

Divide both sides by 3 to get;

P_a = ⅓P_b

Thus, pressure in cylinder A must be one third of pressure in cylinder B

3 0
3 years ago
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