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bazaltina [42]
3 years ago
6

If someone throws a 3 gram fry accelerating at 5 meter/second2, what is the fry’s force?

Physics
1 answer:
Alex3 years ago
3 0

Answer:

0.015 m/s2

Explanation:

Using Newtons 2nd law.

F = ma where F = Force applied, m = mass of the object and a = acceleration acquired.

So substitute the values in SI units.

m = \frac{3}{1000} kg

Therefore F = 0.003×5 = 0.015 m/s2

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Pressure between the inside chest wall and the outside of the lungs normally remains negative. Explain how pressure inside the l
STatiana [176]

Answer:

by doing rapid shallow breathing and pursed lip breathing  

Explanation:

Pressure with in the chest wall and the outside of the lungs remains negative because the intrapleural pressure is always lesser than the intra-alveolar pressure or atmospheric pressure. In general forced expiration leads to an increasing positive pressure in pleura. This happens because the pleura airway gets compressed and the size of airway reduces thereby forcing expiration.  

People who are able to resist airway can increase airflow by doing rapid shallow breathing and pursed lip breathing  

3 0
4 years ago
The diagram below represents a structure in the cell
dusya [7]
It might be CO2 but I’m not sure since I haven’t learned this since 5th grade
8 0
3 years ago
Assume that a pitcher throws a baseball so that it travels in a straight line parallel to the ground. The batter then hits the b
sertanlavr [38]

Answer:

v_f = -25.9 m/s

Explanation:

- The complete question is as follows:

" Assume that a pitcher throws a baseball so that it travels in a straight line parallel to the ground. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. Define the direction the pitcher originally throws the ball as the +x direction.

Now assume that the pitcher in Part D throws a 0.145-kg baseball parallel to the ground with a speed of 32 m/s in the +x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. What is the ball's velocity just after leaving the bat if the bat applies an impulse of −8.4N⋅s to the baseball?"

Given:

- mass of baseball m = 0.145 kg

- Speed before impact v_i = 32 m/s

- Speed after impact v_f

- Impulse applied by the bat I = - 8.4Ns

Find:

What is the ball's velocity just after leaving the bat

Solution:

- Impulse is the change in linear momentum of the ball according to Newton's second law of motion:

                              I = m* ( v_f - v_i )

- Taking the + from pitcher to batsman and - from batsman to pitcher.

- Plug in the values:

                              -8.4 = 0.145* ( v_f - (32) )

                               v_f = -57.93103 + 32

                               v_f = -25.9 m/s

4 0
3 years ago
Two isolated copper plates, each of area 0.40 m2, carry opposite charges of magnitude 7.08 × 10-10 C. They are placed opposite e
polet [3.4K]

Answer:

The potential difference between the plates is 8 V.

Explanation:

Given that,

Area of plates = 0.40 m²

Charge q=7.08\times10^{-10}\ C

Distance = 4.0 cm

We need to calculate the electric field

Using for formula of electric field

E=\dfrac{2q}{2\epsilon_{0}A}

Where, q = charge

A = area

Put the value into the formula

E=\dfrac{7.08\times10^{-10}}{8.85\times10^{-12}\times0.40}

E=200\ V/m

We need to calculate the potential difference between the plates

Using formula of potential difference

V=E\times d

Where, E = electric field

d = distance

Put the value into the formula

V=200\times0.04

V=8\ V

Hence, The potential difference between the plates is 8 V.

3 0
4 years ago
Which of the following statements is true? A. Both warming up and cooling down or important. B. It is more important warm up the
Alenkasestr [34]

Answer:

Both warming up and cooling down or not important

8 0
3 years ago
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