All categories

3 years ago

Find the interquartile range for the Dara set :10,3,8,6,9,12,13

Mathematics

2 answers:

jonny [76]3 years ago

8 0

A
The answer for that problem is c

goldfiish [28.3K]3 years ago

5 0

Work

(3, 6, 8,) 9, (10, 12, 13)

The median is 9.

Q1 is 6

Q3 is 12

12 - 6 = 6

Answer

C.) 6

You might be interested in

A team won 8 of the 24 games it played in one season .what percentage of the games did it win

Bond [772]

Answer:

The team won 33.33% of their games.

Step-by-step explanation:

Proportion and percentage of games won:

The proportion of games won is the number of games won divided by the total number of games.

The percentage of games won is the proportion multiplied by 100.

We have that:

8 wins in 24 games.

8/24 = 0.3333

0.3333*100 = 33.33%

The team won 33.33% of their games.

4 0

4 years ago

Maths

tamaranim1 [39]

Answer:

12 : 1

Step-by-step explanation:

The volume of a cylinder:

V = πr²h, where r-radius, h-height

New dimensions of the cake:

r1 → 2r and h1→ 3h

The volume of the bigger cake:

V1 = π*(2r)²*(3h) = 12*πr²h = 12V
V1/V = 12

The ration of volumes is 12 : 1

5 0

4 years ago

What is the slope of the line that passes through the points (3,4) and (0, -2)

alekssr [168]

I got -2 as the slope hope this helps:)

4 0

3 years ago

Read 2 more answers

A home appliance salesperson wants to earn a total of 3,600 next month including his base salary and commissions. He earns a bas

BARSIC [14]

Answer:

He must sell $14000 of merchandise

Step-by-step explanation:

The salesperson earns a base salary of $800

This means that he must make

$3600 - $800 = $2800 worth of commisions

Let x, be the value of the mechandise that he needs to sell.

This means that

x*0.20 = $2800

x = $2800/0.20

x = $14000

He must sell $14000 of merchandise

6 0

3 years ago

What is the solution to the system of linear equations? −9x+4y=55 −11x+7y=82

LuckyWell [14K]

Here is my process with mathematical expression interpreter, LaTeX. Full process given below to obtain the values of variable "x" and "y" altogether, solutions to these system of linear equations.

$\begin{bmatrix}-9x & + & 4y & = & 55 & \bf{- - - \: Eq. \: 1} \\ \\ -11x & + & 7y & = & 82 & \bf{- - - \: Eq. \: 2} \end{bmatrix}$

Now here, we should isolate a variable, or take it as a separate form to find the equation, and furthermore substitute the value of variable "y" into the original isolation of "x", to obtain both the solutions for this linear system of equation. Perform this on equation number 1 (Eq. 1).

Subtract the variable attached value by "4y" on both the sides, in current expression.

$\mathbf{-9x + 4y - 4y = 55 - 4y}$

$\mathbf{-9x = 55 - 4y}$

Both the sides, perform a division of value "-9".

$\mathbf{\dfrac{-9x}{-9} = \dfrac{55}{-9} - \dfrac{4y}{-9}}$

$\mathbf{x = \dfrac{55 - 4y}{-9}}$

$\mathbf{x = - \dfrac{55 - 4y}{9}}$

Substitute or just plug the value of newly obtained expression for variable "x" into Equation, numbered as "2" (Eq. 2.) and isolate further for the variable "y", to obtain first solution for this linear equation.

$\mathbf{-11 \Bigg(- \dfrac{55 - 4y}{9} \Bigg) + 7y = 82}$

$\mathbf{\dfrac{(55 - 4y) \times 11}{9} + 7y = 82}$

Multiply both the sides by a value of "9".

$\mathbf{\dfrac{(55 - 4y) \times 11}{9} + 7y \times 9 = 82 \times 9}$

$\mathbf{11 (55 - 4y) + 63y = 738}$

$\mathbf{605 - 44y + 63y = 738}$

$\mathbf{605 + 19y = 738}$

Subtract both the sides by a value of "- 605".

$\mathbf{605 + 19y - 605 = 738 - 605}$

$\mathbf{19y = 133}$

Divide both the sides by "19".

$\mathbf{\dfrac{19y}{19} = \dfrac{133}{19}}$

$\boxed{\mathbf{y = 7}}$

Substitute this variable value of "y = 7" , into our original isolation for variable "x", the expression is to be substituted by that value to complete the solutions for the linear equations. That is:

$\mathbf{x = - \dfrac{55 - 4y}{9}; \quad y = 2}$

$\mathbf{\therefore \quad x = - \dfrac{55 - 4 \times 7}{9}}$

$\mathbf{\therefore \quad x = - \dfrac{55 - 28}{9}}$

$\mathbf{x = - \dfrac{27}{9}}$

$\boxed{\mathbf{x = - 3}}$

Finalised solutions for these linear system of equations for two components , is:

$\boxed{\mathbf{\underline{\therefore \quad Final \: Solutions \: for \: these \: System \: of \: Linear \: Equations: \: x = - 3, \: \: y = 7}}}$

Hope it helps.

5 0

3 years ago