Answer:
Temperature on the inside ofthe box
Explanation:
The power of the light bulb is the rate of heat conduction of the bulb, 
The thickness of the wall, L = 1.2 cm = 0.012m
Length of the cube's side, x = 20cm = 0.2 m
The area of the cubical box, A = 6x²
A = 6 * 0.2² = 6 * 0.04
A = 0.24 m²
Temperature of the surrounding, 
Temperature of the inside of the box, 
Coefficient of thermal conductivity, k = 0.8 W/m-K
The formula for the rate of heat conduction is given by:
Answer:
0.2 x 100
Explanation:
Engineering strain is the original crossection/original crossection
cold work percentage is
original crossection/original crossection x 100
Answer:

Explanation:
Hello,
In this case by combining the first and second law of thermodynamics for this ideal gas, we can obtain the following expression for the differential of the specific entropy <em>at constant pressure</em>:

Whereas Rg is the specific ideal gas constant for the studied gas; thus, integrating:

We obtain the expression to compute the specific entropy change:

Best regards.
Answer:
Mass of cement used is 62.5 lb
Mass of gravel used is 225 lb
Explanation:
The ratio given here is cement to sand to gravel = 1 : 2.4 : 3.6
So, for 150 lb of sand
C : S : G = 1 : 2.4 : 3.6

Mass of cement used is 62.5 lb

Mass of gravel used is 225 lb
Answer:
a) 927 MPa
b)The specimen will experience fracture
Explanation:
a) Calculate critical stress for brittle fracture
σ = fracture toughness / (y √ π * surface crack)
= 45 / ( 1
)
= 927 MPa
b) since critical stress( 927 MPa) < 1000 MPa
hence : The fracture will occur