The correct answer would more than likely have to be true, i’ve had this question before not to long ago.
Answer: E
=
1.55
⋅
10
−
19
J
Explanation:
The energy transition will be equal to 1.55
⋅
10
−
1
J
.
So, you know your energy levels to be n = 5 and n = 3. Rydberg's equation will allow you calculate the wavelength of the photon emitted by the electron during this transition
1
λ =
R
⋅
(
1
n
2
final −
1
n
2
initial )
, where
λ
- the wavelength of the emitted photon;
R
- Rydberg's constant - 1.0974
⋅
10
7
m
−
1
;
n
final
- the final energy level - in your case equal to 3;
n
initial
- the initial energy level - in your case equal to 5.
So, you've got all you need to solve for λ
, so
1
λ =
1.0974
⋅10 7
m
−
1
⋅
(....
−152
)
1
λ
=
0.07804
⋅
10
7
m
−
1
⇒
λ
=
1.28
⋅
10
−
6
m
Since
E
=
h
c
λ
, to calculate for the energy of this transition you'll have to multiply Rydberg's equation by
h
⋅
c
, where
h
- Planck's constant -
6.626
⋅
10
−
34
J
⋅
s
c
- the speed of light -
299,792,458 m/s
So, the transition energy for your particular transition (which is part of the Paschen Series) is
E
=
6.626
⋅
10
−
34
J
⋅
s
⋅
299,792,458
m/s
1.28
⋅
10
−
6
m
E
=
1.55
⋅
10
−
19
J
The result of the procedure is that the copper strip should go through oxidation.
<h3>How to explain the procedure?</h3>
The copper strip should be considered as the anode and the nail should be considered as the cathode.
The anode is the electrode of an electrochemical cell at which oxidation occurs. The anode should be + while the cathode should be negative. Both should be placed in the tank that should be filled with the electrolyte solution.
Learn more about oxidation on:
brainly.com/question/25886015
#SPJ1
Answer:
The farther away the planet the slower the revolution around the earth. the closer the faster.
Explanation:
its like a tetherball pole when it wraps around it gets closer and spins faster and faster untill it stops. Brainliest?
when Cl2 is dissolved in water it generates ClO which is a good oxidizing agent since it gives out atomic oxygen. but dissolution of F2 cannot generate atomic oxygen since F is more electronegative than O
