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madreJ [45]
3 years ago
8

O O O A. Molecule B. Compound C. Both

Chemistry
1 answer:
ra1l [238]3 years ago
5 0
This doesn’t seem like the full question
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Empirical formula of n3h9
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What is the numerical value of Kc for the following reaction if the equilibrium mixture contains 0.51 M
Goryan [66]

The  numerical value  of Kc  is 1.129  x10^4

 

<u><em>  Explanation</em></u>

C3H6O +4O2→  3 CO2 + 3H2O

KC  is the ratio  of  concentration of the   product  over  the reactant.

Each concentration of  product and  reactant   are raised  to the power  of  its coefficient.

Therefore the KC  expression  of  equation above  is

Kc=[ (Co2)^3 (H2O)^3]  / [(C3H6O) (O2)^4)]

 Kc  =[(1.8^3) x  (2.0^3)] / [(0.51)  x (0.30^4)] =1.129  x10^4


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