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2 years ago

O O O A. Molecule B. Compound C. Both

Chemistry

1 answer:

ra1l [238]2 years ago

5 0

This doesn’t seem like the full question

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A chemical change combining two elements results in?

Neporo4naja [7]

Answer:

When two distinct elements are chemically combined for example, chemical bonds form between their atoms, the result is called a chemical compound. Most elements on Earth bond with other elements to form chemical compounds, such as sodium and Chloride, which combine to form table salt.

8 0

3 years ago

Which of the following is true of atoms with very low electronegativity

Katarina [22]

Answer:

well there is no chose here is my best option i would chose

1 Electronegativity is the ability of an atom to attract electrons.

Explanation:

5 0

2 years ago

Can someone help me please and please show work

FinnZ [79.3K]

Answer:

Average of the trial is: 288.50 C

Percent Error: 3.83%

Explanation:

(291 + 287 + 295 + 281) : 4 = 288.50 C

Average: 288.50 C

Percent Error: {(300 - 288.50) : 300} x 100% = 3.83 %

4 0

3 years ago

Hello there

melamori03 [73]

if density = m(mass) / v(volume) then the answer would be 3

6 0

3 years ago

An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g

vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= $\frac{33.8 g solute}{100 g solution}$ x $\frac{1.15 g solution}{1 ml}$ x $\frac{1 mol solute}{145.6 g solute}$ x $\frac{1000 ml}{1 L}$

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x $\frac{1 mol solute}{145.6 g}$ = 0.232 mol

mol H20= 66.2 g H₂O x $\frac{1 mol H2O}{18 g}$

Finally, the mol fraction of solute (Xsolute) is calculated as follows:

Xsolute= $\frac{mol solute}{total mol}= \frac{mol solute}{mol solute + mol H2O}=\frac{0.232 mol}{0.232 mol + 3.677 mol}$

Xsolute= 0.059

4 0

3 years ago