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3 years ago

Which particles in an atom could demonstrate that opposite charges attract?

Physics

2 answers:

Oxana [17]3 years ago

4 0

Answer:

Choice D. a proton and an electron.

Explanation:

Each proton carries a positive charge of $+1$ unit.

Each electron carries a negative charge of $-1$ unit.

As their name suggests, neutrons are neutral. They do not carry any electrostatic charge. Because of that, neutrons can't attract or repel neutrons or protons with electrostatic forces.

On the other hand, electrons and protons carry opposite charges. Therefore, an electron and a proton would attract each other electrostatically.

However, since protons are all positive, two protons would repel each other electrostatically.

kompoz [17]3 years ago

3 0

Answer:

The correct answer is D

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Two neutron stars are separated by a distance of 1.0 x 1012 m. They each have a mass of 1.0 x 1028 kg and a radius of 1.0 x 103

son4ous [18]

To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.

Gravitational potential energy can be defined as

$PE = -\frac{GMm}{R}$

As M=m, then

$PE = -\frac{Gm^2}{R}$

Where,

m = Mass

G =Gravitational Universal Constant

R = Distance /Radius

PART A) As half its initial value is u'=2u, then

$U = -\frac{2Gm^2}{R}$

$dU = -\frac{2Gm^2}{R}$

$dKE = -dU$

Therefore replacing we have that,

$\frac{1}{2}mv^2 =\frac{Gm^2}{2R}$

Re-arrange to find v,

$v= \sqrt{\frac{Gm}{R}}$

$v = \sqrt{\frac{6.67*10^{-11}*1*10^{28}}{1*10^{12}}}$

$v = 816.7m/s$

Therefore the velocity when the separation has decreased to one-half its initial value is 816m/s

PART B) With a final separation distance of 2r, we have that

$2r = 2*10^3m$

Therefore

$dU = Gm^2(\frac{1}{R}-\frac{1}{2r})$

$v = \sqrt{Gm(\frac{1}{2r}-\frac{1}{R})}$

$v = \sqrt{6.67*10^{-11}*10^{28}(\frac{1}{2*10^3}-\frac{1}{10^{12}})}$

$v = 1.83*10^7m/s$

Therefore the velocity when they are about to collide is $1.83*10^7m/s$

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3 years ago

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Semenov [28]

Answer:

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Explanation:

even though he is moving quicker doesn't mean he will be packing more force in the collision

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3 years ago

A commonly used unit of electrical energy.

ladessa [460]

The two most common units of electric energy is Watts or hertz.

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4 years ago

Any help would be highly appreciated, preferably with steps too!

qwelly [4]

Answer:

Help with what:?

Explanation:

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3 years ago

The period P of a pendulum depend on its length , mass as well as the acceleration due to gravity . Use dimensional analysis to

Savatey [412]

Explanation:

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Length has units of meters (m).

Mass has units of kilograms (kg).

Acceleration has units of meters per second squared (m/s²).

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s = √(m / (m/s²))

Therefore:

P = k √(L/g)

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3 years ago