3 years ago

1. Order the materials from smallest refractive index to largest refractive index.

Physics

1 answer:

kakasveta [241]3 years ago

5 0

Air = 1

Water = 1.33

Glass = 1.52

Quartz = 1.46

Diamond = 2.42

You might be interested in

A spring that is compressed 14.5 cm from its equilibrium position stores 2.99 J of potential energy. Determine the spring consta

strojnjashka [21]

Answer:

284.4233 N/m

Explanation:

k = Spring constant

x = Compression of spring = 14.5 cm

U = Potential energy = 2.99 J

The potential energy of a spring is given by

$U=\dfrac{1}{2}kx^2$

Rearranging to get the value of k

$\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 2.99}{0.145^2}\\\Rightarrow k=284.4233\ N/m$

The spring constant is 284.4233 N/m

7 0

3 years ago

Where might water be found on the moon

Cerrena [4.2K]

Water Could be Found in the frozen Ice on the moon. it would most likely be underground however

8 0

2 years ago

Read 2 more answers

Some scientists look at the boundary between two biological communities and see a sharp dividing line. Others looking at the sam

Elena L [17]

This is for the reason that individuals are not continually taking a gander at precisely the same, and on the grounds that individuals' psyches of ten work distinctively and process data in marginally extraordinary ways getting diverse understandings of similar information.

7 0

3 years ago

A force of 5N compresses a spring by 4cm. Find the force constant of the spring.

marissa [1.9K]

Answer:

k = 1,250 N/m

Explanation:

Use the formula F=kx, with F=5N and x=0.04m

Then the spring constant (k) is 5/0.04

6 0

2 years ago

The amount of mass an object has per its volume is known as ___________.. Select one of the options below as your answer:. A. pr

White raven [17]

<span>The amount of mass an object has per its volume is known as density. The correct option among all the options that are given in the question is the third option or the last option or option "C". I hope that this is the answer that you were looking for and the answer has actually come to your great help.</span>

3 0

3 years ago