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Montano1993 [528]
3 years ago
14

What is (-5) the 2 is an exponent just so you know

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

Answer:

25

Step-by-step explanation:

(-5)^2 = 25, since -5 x -5 is 25.

Now, if the -5 hadn't been in parenthesis, -5^2 would be read as -(5 x 5), and would equal -25.

<em>Brainliest, please! I'm so close to becoming an Expert!</em>

ValentinkaMS [17]3 years ago
7 0

Answer:

25

Step-by-step explanation:

(-5)^2

(-5)*(-5)

25

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I need the solution. Please give steps<br> y = 10x + 20<br> y = 20x + 10
lidiya [134]

Answer:

If your trying to answer for X, here is how you do it.

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X =  Y/10 − 2

Or

X = \frac{Y}{10} − 2

For the other equation " Y = 20x + 10 ", it's the exact same thing. Isolate the variable 'X' by dividing each side by factors that don't contain the variable 'X', to get your answer:

X = Y/20 − 1/2

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8 0
3 years ago
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Directions: Use substitution to solve the systems of equations. Show your work please.
Len [333]

Hey there!

To use substitution, you substitute one of the equations into the other for one of the variables.

Since thhe first equation is already solved for y, let's substitute that one into the second equation.

Before substitution: x - y = 1

After substitution:    x - 2x = 1

See how we replaced the y with 2x? This is because the first equation is y = 2x.

Combine like terms.

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Multiply each side by -1 so we get the value of x, not -x.

x = -1

We can now solve for y using the 1st equation, substituting the value for x into it.

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After:    y = 2(-1)

Multiply the two together.

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Let's check this in the second equation, so we know we didn't make a mistake somewhere.

Before: x - y = 1

After:   (-1) - (-2) = 1

Subtracting a negative is the same as adding a positive, so let's notate it that way to make it easier.

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Add.

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Since both sides are equal, that means we've got the correct solution.

The notation for our answer will be (x, y) since it is a point on a graph.

Your final answer is (-1, -2).

Hope this helps!

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3 years ago
Find the length of the side f .
algol13
I am pretty sure the answer is 10. Someone correct me if I'm wrong
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