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Fantom [35]
3 years ago
5

What will happen if TWO light bulbs are placed at point D, and point B is closed?

Chemistry
1 answer:
AlexFokin [52]3 years ago
8 0

Answer: the light bulbs will be dimmer than usual

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Utilizing dimensional analysis find the number of inches in a kilometer given that 1 inch equals 2.54 cm
hodyreva [135]
To solve this problem, separate it into chunks that you know. You know that there are 2.54 centimeters in 1 inch. You know that there are 100 centimeters in 1 meter. You know that there are 1000 meters in a kilometer. Therefore, we'll convert in this order: 1) from kilometers to meters, 2) from meters to centimeters, and 3) from centimeters to inches.
1) 1km × 1000m/1km
= 1000m
2) 1000m × 100cm/1m
= 100000cm
3) 100000cm × 1in/2.54cm
≈ 39370in
So, there are approximately 39370 inches in a kilometer.
4 0
4 years ago
Keera decided to investigate how the growth of plants is affected by the time of day it is watered. She placed an equal amount o
Arada [10]
The time of day the plants are watered is the independent variable. Keera did everything else the same for each plant.
7 0
3 years ago
The rock in a lead ore deposit contains 89 % PbS by mass. How many kilograms of the rock must be processed to obtain 1.5 kg of P
Zolol [24]

Answer:

Approximately 1.9 kilograms of this rock.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Pb: 207.2;
  • S: 32.06.

To answer this question, start by finding the mass of Pb in each kilogram of this rock.

89% of the rock is \rm PbS. There will be 890 grams of \rm PbS in one kilogram of this rock.

Formula mass of \rm PbS:

M(\mathrm{PbS}) = 207.2 + 32.06 = 239.26\; g\cdot mol^{-1}.

How many moles of \rm PbS formula units in that 890 grams of \rm PbS?

\displaystyle n = \frac{m}{M} = \rm \frac{890}{239.26} = 3.71980\; mol.

There's one mole of \rm Pb in each mole of \rm PbS. There are thus \rm 3.71980\; mol of \rm Pb in one kilogram of this rock.

What will be the mass of that \rm 3.71980\; mol of \rm Pb?

m(\mathrm{Pb}) = n(\mathrm{Pb}) \cdot M(\mathrm{Pb}) = \rm 3.71980 \times 207.2 = 770.743\; g = 0.770743\; kg.

In other words, the \rm PbS in 1 kilogram of this rock contains \rm 0.770743\; kg of lead \rm Pb.

How many kilograms of the rock will contain enough \rm PbS to provide 1.5 kilogram of \rm Pb?

\displaystyle \frac{1.5}{0.770743} \approx \rm 1.9\; kg.

5 0
4 years ago
If you get the question right i will give brainliest (HINT ITS NOT A)
storchak [24]

Answer:

Explanation:

its b, i looked it up

5 0
3 years ago
Classify these compounds as acid, base, salt, or other.? 1. ch3oh 3. hno3 5. nabr
ELEN [110]
<span> </span><span>1. Alcohol(other) 
3. Acid 
5. Salt 

</span>
5 0
3 years ago
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