Which compound would most likely turn litmus paper to a red color?

Calculate the ph of the solution resulting from the addition of 85.0 ml of 0.35 m hcl to 30.0 ml of 0.40 m aniline (c6h5nh2). kb

stiv31 [10]

Answer:

pH = 0.81

Explanation:

HCl reacts with aniline, thus:

C₆H₅NH₂ + HCl → C₆H₅NH₃⁺ + Cl⁻

Moles of HCl are:

0.085L × (0.35mol HCl / L) = 0.02975mol HCl

Moles of aniline are:

0.030L × (0.40mol HCl / L) = 0.012mol aniline

Thus, after reaction, will remain:

0.02975mol - 0.012mol = 0.01775mol HCl

Moles of HCl in solution are equal to moles of H⁺, thus, moles of H⁺ are: 0.01775mol H⁺

As total volume is 85.0mL + 30.0mL = 115.0mL ≡ 0.115L

0.01775mol / 0.115L = 0.1543M

pH of solution = -log[H⁺]

pH = -log 0.1543M

pH = 0.81

3 0

3 years ago

Read 2 more answers

Consider the equilibrium reaction. 4A+B↽−−⇀3C After multiplying the reaction by a factor of 2, what is the new equilibrium equat

ss7ja [257]

8A+2B——> 6C
since you multiply by a factor of 2 you do that to each letter
4*2=8
1*2=2
3*2=6

5 0

3 years ago

NEED HELP ASAP!!! As atmospheric carbon dioxide increases, the amount of carbon dioxide dissolved in the ocean _____.

Dennis_Churaev [7]

Answer:

If temperature stays the same, the amount of carbon dioxide dissolved in the ocean would increase.

Explanation:

The carbon dioxide in the air ( ${\rm CO_{2}}\, (g)$ ) and the carbon dioxide dissolved in the ocean ( ${\rm CO_{2}}\, (aq)$ ) are in a solution equilibrium:

${\rm CO_{2}}\, (g) \rightleftharpoons {\rm CO_{2}}\, (aq)$ .

Assume that the concentration of carbon dioxide in the air ( ${\rm CO_{2}}\, (g)$ ) increased while temperature stayed the same.

By Le Ch $^{}$ atelier's Principle, the solution equilibrium ${\rm CO_{2}}\, (g) \rightleftharpoons {\rm CO_{2}}\, (aq)$ would shift to offset this increase in ${\rm CO_{2}}\, (g)$ concentration. Specifically, this equilibrium would reduce the amont of ${\rm CO_{2}}\, (g)\!$ in the system by converting more atmospheric ${\rm CO_{2}}\, (g)\!\!$ to ${\rm CO_{2}}\, (aq)\!$ dissolved in the ocean. Therefore, the concentration of ${\rm CO_{2}}\, (aq)\!\!$ dissolved in the ocean would increase.

8 0

3 years ago

A mixture of He, Ne, and Ar gases at a particular temperature has partial pressures of 0.75 atm He, 0.30 atm Ne, and 0.62 atm Ar

inessss [21]

Answer:

The order of mole fraction in increasing order will be:

$\chi_{Ne}$

Explanation:

Relation between mole fraction and partial pressure of the component is given as:

$p_i=P\times \chi_i$

Where :P = Total pressure of the mixture

$p_i$ = partial pressure of the i component

$\chi_i$ = Mole fraction of the i component

We have :

Partial pressure of the helium gas , $p_{He}$ = 0.75 atm

Partial pressure of the neon gas, $p_{Ne}$ = 0.30 atm

Partial pressure of the argon gas , $p_{Ar}$ = 0.62 atm

As we can see that from the above equation, that partial pressure and mole fraction are directly linked to each other.

$p_i\propto \chi_i$

So, the gas with higher value of partial; pressure will have higher value of mole fraction in the mixture.

So, the order of partial pressure from lowest to highest is:

$p{Ne}$

And hence the order of mole fraction will also be same :

$\chi_{Ne}$

5 0

4 years ago

What does the number of valence electrons determine?

N76 [4]

Valence electrons are the electrons in the outermost shell of an element on the periodic table. Atoms want to be able to have a full outer shell and they can share or trade electrons in order to achieve this. Valence electrons are also super super important in chemical reactions. The number of valence electrons determines what group that specific atom or element is in on the periodic table. This affects the reactivity of the element.

4 0

4 years ago