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erica [24]
3 years ago
11

A diathermy machine, used in physiotherapy, generates electromagnetic radiation that gives the effect of "deep heat" when absorb

ed in tissue. If the radiation's frequency is 27.17 MHz, what is its wavelength?
Physics
1 answer:
zloy xaker [14]3 years ago
8 0

Answer:

The wavelength of the radiation is 11.04 m.

Explanation:

Given that,

The radiation's frequency is 27.17 MHz.

1\ MHz=10^6\ Hz\\\\27.17\ Mhz=27.17\times 10^6\ Hz

We need to find the wavelength of the radiation. It can be calculated using the formula of speed of electromagnetic wave as :

c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8\ m/s}{27.17\times 10^6\ Hz}\\\\\lambda=11.04\ m

So, the wavelength of the radiation is 11.04 m.

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An astronaut exploring a distant solar system lands on an unnamed planet with a radius of 2530 km. When the astronaut jumps upwa
Natali [406]

Answer:

1.38*10^18 kg

Explanation:

According to the Newton's law of universal gravitation:

F=G*\frac{m_a*m_p}{r^2}

where:

G= Gravitational constant (6.674×10−11 N · (m/kg)2)

ma= mass of the astronaut

mp= mass of the planet

F=m_a.a\\(v_f )^2=(v_o)^2+2.a.\Delta y\\\\a=\frac{(v_f)^2-(v_o)^2}{2.\Delta y}\\\\a=\frac{(0)^2-(4.29m/s)^2}{2.0.64m}=14.38m/s^2\\\\F=m_a*14.38m/s^2

so:

m_a*14.38m/s^2=(6.674*10^{-11}N.(m/kg)^2)*\frac{m_a.m_p}{(2.530*10^3m)^2}\\m_p=\frac{14.38m/s^2(2.530*10^3m)^2}{(6.674*10^{-11}N.(m/kg)^2)}\\\\m_p=1.38*10^{18}kg

7 0
3 years ago
Thermal energy transfers from a cup of tea at 350 K to the hand holding it. <br> A)True<br> B)False
Alexandra [31]

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true

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Does wax paper, aluminum foil, or plastic wrap cause more friction
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A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material
My name is Ann [436]

Answer:

a)   C = 4,012 10⁻¹⁴ F, b)  Q = 1.6 10⁻¹¹ C , c)   U = 3.21 10⁻¹¹ J

Explanation:

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       C = k e₀ A / d

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       C = 4 8.85 10⁻¹² 17 10⁻⁴ / 0.150 10⁻²

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b) let's look  the charge

        C = Q / ΔV

         Q = C ΔV

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         Q = 1.6 10⁻¹¹ C

c) The stored energy

        U = ½ C ΔV²

        U = ½ 4,012 10⁻¹⁴  400²

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