Ask question

Ask question

All categories

3 years ago

11

A diathermy machine, used in physiotherapy, generates electromagnetic radiation that gives the effect of "deep heat" when absorb

ed in tissue. If the radiation's frequency is 27.17 MHz, what is its wavelength?

1 answer:

zloy xaker [14]3 years ago

8 0

Answer:

The wavelength of the radiation is 11.04 m.

Explanation:

Given that,

The radiation's frequency is 27.17 MHz.

$1\ MHz=10^6\ Hz\\\\27.17\ Mhz=27.17\times 10^6\ Hz$

We need to find the wavelength of the radiation. It can be calculated using the formula of speed of electromagnetic wave as :

$c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8\ m/s}{27.17\times 10^6\ Hz}\\\\\lambda=11.04\ m$

So, the wavelength of the radiation is 11.04 m.

You might be interested in

A robin in flight has 20.8 J of PE when it is 27.6 m high. What is the mass of the robin? (Unit = kg)

schepotkina [342]

Answer:

<h2> $\boxed{ \bold{ \purple{0.0769 \: kg \: }}}$ </h2>

Explanation:

$\sf{Potential Energy ( P.E ) \: = \: 20.8 \: joule}$

$\sf{distance \: = 27.6 \: metre}$

$\sf{mass = }$ ?

$\sf{acceleration \: due \: to \: gravity = 9.68 \: {metre \: per \: second}^{2} }$

Now, let's find the mass:

$\sf{PE \: = mass \times gravity \: \times \: distance}$

plug the values

⇒ $\sf{20.8 = m \times 9.8 \times 27.6}$

Multiply the numbers

⇒ $\sf{20.8 = 270.48 \: m}$

Swap the sides of the equation

⇒ $\sf{270.48m = 20.8}$

Divide both sides of the equation by 270.48

⇒ $\sf{ \frac{270.48m}{270.48} = \frac{20.8}{270.48} }$

Calculate

⇒ $\sf{0.0769}$ kg

Hope I helped!

Best regards!!

7 0

3 years ago

Read 2 more answers

Una ambulancia se aleja de una persona en línea recta a razón de 30 m/s. Si la sirena

saul85 [17]

Answer:

$f_o=331.046Hz$

Explanation:

Use Doppler effect equation:

The Doppler effect is a physical phenomenon where an apparent change in wave frequency is presented by a sound source with respect to its observer when that same source is in motion. The general equation is given by:

$f_o=f_s\frac{v\pm v_o}{v\mp v_s} \\\\Where:\\\\f_s=Actual\hspace{3}frequency\hspace{3}of\hspace{3}the\hspace{3}sound\hspace{3}waves\\f_o=Observed\hspace{3}frequency\\v=Speed\hspace{3}of\hspace{3}the\hspace{3}sound\hspace{3}waves\\v_o=Velocity\hspace{3}of\hspace{3}the\hspace{3}observer\\v_s=Velocity\hspace{3}of\hspace{3}the\hspace{3}source$

When the observer moves towards the source $v_o$ is positive.

When the observer moves away from the source $v_o$ is negative.

When the source moves towards the observer $v_s$ is negative.

When the source moves away from the observer $v_s$ is positive.

Since the problem don't give us aditional information let's assume:

$v=343m/s$

Which is the speed of sound in air.

And using the information provided by the problem:

$v_s=30m/s\\v_o=0\\f_s=360Hz$

$f_o=f_s\frac{v}{v+v_s} =360*\frac{343}{343+30} =331.0455764\approx 331.046Hz$

The frequency perceived by the person is 331.046Hz

<em><u>Translation:</u></em>

<em><u></u></em>

Usa la ecuación del Efecto Doppler:

El efecto Doppler es un fenómeno físico en el que una fuente de sonido presenta un cambio aparente en la frecuencia de onda con respecto a su observador cuando esa misma fuente está en movimiento. La ecuación general viene dada por:

$f_o=f_s\frac{v\pm v_o}{v\mp v_s} \\\\Donde:\\\\f_s=Frecuencia\hspace{3}real\hspace{3}de\hspace{3}las\hspace{3}ondas\hspace{3}sonoras\\f_o=Frecuencia\hspace{3}observada(percibida)\\v=Velocidad\hspace{3}de\hspace{3}las\hspace{3}ondas\hspace{3}sonoras\\v_o=Velocidad\hspace{3}del\hspace{3}observador\\v_s=Velocidad\hspace{3}de\hspace{3}la\hspace{3}fuente$

Cuando el observador se mueve hacia la fuente $v_o$ es positivo.

Cuando el observador se aleja de la fuente es $v_o$ negativo.

Cuando la fuente se mueve hacia el observador $v_s$ es negativa.

Cuando la fuente se aleja del observador $v_s$ es positiva.

Como el problema no nos da información adicional, supongamos que:

$v=343m/s$

La cuál es la velocidad del sonido en el aire.

Y utilizando la información proporcionada por el problema:

$v_s=30m/s\\v_o=0\\f_s=360Hz$

$f_o=f_s\frac{v}{v+v_s} =360*\frac{343}{343+30} =331.0455764\approx 331.046Hz$

La frecuencia percibida por la persona es 331.046Hz

5 0

3 years ago

A hiker leaves her camp and walks 3.5 km in a direction of 55° south of west to the lake. after a short rest at the lake, she hi

3241004551 [841]

Let's choose east as positive x-direction and south as positive y-direction. We can resolve the two displacement along these two axes:

- Displacement 1 (3.5 km, $55^{\circ}$ south of west

$d_{1x}=-(3.5 km)( cos 55^{\circ})=-2.01 km$

$d_{1y}=(3.5 km)( sin 55^{\circ})=2.87 km$

- Displacement 2 (2.7 km, $16^{\circ}$ east of south

$d_{2x}=(2.7 km)( sin 16^{\circ})=0.74 km$

$d_{1y}=(2.7 km)( cos 16^{\circ})=2.60 km$

So, the total components on the two directions are

$d_x = -2.01 km+0.74 km=-1.27 km$

$d_y=2.87 km+2.60 km=5.47 km$

And the magnitude of the hiker's resultant displacement is

$d=\sqrt{(1.27 km)^2+(5.47 km)^2}=5.6 km$

8 0

3 years ago

Read 2 more answers

Fill in the blanks. The electrostatic force between two objects is proportional to the ____________________ of the distance ____

Shkiper50 [21]

Write an equation to calculate the force between two objects if the product of their charges is 10.0 × 10-4 C. (Note: Use the variable R for the distance between the charges.)

F = 900 ÷_________

6 0

3 years ago

Read 2 more answers

Help now WILL MARK BRAINLEST

Dmitry_Shevchenko [17]

Answer:

point a and c

Explanation:

point a and c

3 0

3 years ago