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3 years ago

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According to Auto Week magazine, a Chevrolet Blazer traveling at 60 mph (97 km/h) can stop in 8 m on a level road. Determine the

coefficient of friction between the tires and the road. Do you think this is coefficient of kinetic or static friction? Explain.

1 answer:

MrRissso [65]3 years ago

6 0

Check the attached file for the answer.

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What is peer review.why is it important

madam [21]

Acc to

Publisso

Peer review is subjecting the author's scholarly work and research to the scrutiny of other experts in the same field to check its validity and evaluate its suitability for publication.

A peer review helps the publisher decide whether a work should be accepted.

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3 years ago

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A stone with a weight of 5.29 N is launched vertically from ground level with an initial speed of 26.0 m/s, and the air drag on

makkiz [27]

Answer:

a) 19.4 m/s

b) 19 m/s

Explanation:

a) In the given question,

the potential energy at the initial point = Ui = 0

the potential energy at the final point = Uf = mgh

the kinetic energy at the initial point = Ki = 1/2 mv₀².

the kinetic energy at the final point = Kf = 0

work done by air= Ea= fh = 0.262 N

Now, using the law of conservation of energy

initial energy= final energy

Ki +Ui = Kf + Uf +Ea

1/2 mv₀² + 0 = 0 + mgh + fh

1/2 mv₀² = mgh + fh

h = v₀²/ 2g (1 +f/w)

calculate m

m= w/g = 5.29 /9.8

= 0.54 kg

h = 20 ²/ (2 x9.80) x (1 0.265/5.29)

h = 19.4 m.

b) 1/2 mv² + 2fh = 1/2 mv₀²

Vg = 19 m/s

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3 years ago

Which part of the brain controls body temperature

astra-53 [7]

<span>Hormone: a chemical message released in the bodyby cells and glands that affects other cells in an organism. Hypothalamus: a part of the brain thatcontrols things like thirst, hunger, body temperature, and the release of many hormones.</span>

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3 years ago

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How long must a tow truck apply a force of 600 N to increase the speed of a 1,500 kg car at rest to 2 m/s?

slega [8]

The time the truck must apply the given force to increase its speed to given value is 5 s.

The given parameters;

<em>applied force, F = 600 N</em>
<em>mass of the truck, m = 1,500 kg</em>
<em>speed of the truck, v = 2 m/s</em>

The force applied to the truck is determined by Newton's second law of motion; <em>which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.</em>

F = ma

$F = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{1500 \times 2}{600} \\\\t = 5 \ s$

Thus, the time the truck must apply the given force to increase its speed to given value is 5 s.

Learn more here:brainly.com/question/1988795

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2 years ago

What is the acceleration of a 10kg pushed by a 5n force

Semenov [28]

Force equals mass times acceleration. Or:
F=ma
Plug it in:
5=10a
5/10=(10a)/10
.5m/s²=a

8 0

3 years ago