To solve this problem it is necessary to apply the concepts related to transformers, that is to say passive electrical device that transfers electrical energy from one electrical circuit to one or more circuits.
From the mathematical definition we have that the relationship between the voltage of the first coil and the second coil is proportional to the number of loops of the first and second loop, that is:

Where
input voltage on the primary coil.
input voltage on the secondary coil.
number of turns of wire on the primary coil.
number of turns of wire on the secondary coil.
Replacing our values we have:



Replacing,


From the same relations of number of turns and the voltage of the first and second coil we also have the relation of electricity and voltage whereby:

Where
= Current Primary Coil
= Current secundary Coil
Therefore:



Therefore the maximum values for the secondary coil of the voltage is 410.56V and Current is 1.87A
Answer:
a) a = - 0.0833 m / s², b) t = 4.4 s
Explanation:
a) this is a kinematics exercise where the acceleration is along the inclined plane
v = v₀ - a t
a = v₀ - v / t
a = 3 - 8/60
a = - 0.0833 m / s²
b) in this case the final velocity is zero
v = v₀ - a t
0 = v₀ - at
t = v₀ / a
t = 28 / 6.4
t = 4.375 s
t = 4.4 s
Answer:
Explanation:
For parallel inductors ,



For series combination
Total inductance
= 16.67 + 20
= 36.67 mH .
reactance of total inductance at 300 kHz
= ω
where ω is angular frequency
= 2πf
= 2 x 3.14 x 300 x 10³ x 36.67 x 10⁻³
= 69.1 x 10³ ohm
Total rms current = Vrms / reactance
= 60 / 69.1 x 10³ A
= .87 x 10⁻³ A
= .87 mA
Answer:
Option C
Explanation:
Given that
Motor force is 250 N
Force of friction is 750 N
Weight is 8500 N
And, the normal force is 8500 N
Now based on the above information
Here length of the rector shows the relative magnitude forward force i.e. 250 N i..e lower than the frictional force i.e. backward and weight i.e. 8500 would be equivalent to the normal force
Answer:
A. Increasing the voltage of the battery
Explanation:
The relationship between voltage, V, current, I and resistance, R, is given as follows;
V = I × R
∴ I = V/R
From the above relationship, the current flowing in the circuit is directly proportional to the voltage of the battery, and inversely proportional to the resistance, 'R', of the circuit
Therefore, increasing the voltage, 'V', of the battery, increases the total current, 'I', flowing in the circuit.