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Liula [17]
3 years ago
7

Calculate the atomic mass of sulfur if the four common isotopes of sulfur have masses of 31.972 amu (95.00 % abundance), 32.971

amu (0.76 %), 33.967 amu (4.22 %), and 35.967 amu (0.014 %).
Chemistry
2 answers:
Gemiola [76]3 years ago
6 0

Answer:32.063 u

Explanation:

The average atomic mass of a chemical element is calculated by taking into account the atomic masses of its naturally occurring isotopes and their respective abundances.

Contact [7]3 years ago
4 0

Answer:

32.060 amu letter B.) plato

Explanation:

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abruzzese [7]

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arsenic (As)

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What is the atomic structure for antimony
djverab [1.8K]

Answer:

Hmm

Explanation:

Elemental antimony adults a layer structure (space group R3m No.166) in which layers consist of fused, ruffled, six-membered rings. The nearest and the next nearest neighbors form and irregular octahedral complex, with the 3 atoms in each layer slightly closer than 3 atoms in the next

Electric configuration : 4d^10 5s^2 5p^3

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Summarize how a dinosaur can become a fossil.
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The dinosaur dies and is washed away in a flood. The body is buried in sediment (mud or sand) and eventually the body is covered. ... Eventually, the fossil skeleton comes to the surface and is discovered.
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3 years ago
Which of the following is one part of a chemical formula for a molecule?
solniwko [45]

D

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8 0
3 years ago
Read 2 more answers
The constant
Zigmanuir [339]

Answer:

75 kJ/mol

Explanation:

The reactions occur at a rate, which means that the concentration of the reagents decays at a time. The rate law is a function of the concentrations and of the rate constant (k) which depends on the temperature of the reaction.

The activation energy (Ea) is the minimum energy that the reagents must have so the reaction will happen. The rate constant is related to the activation energy by the Arrhenius equation:

ln(k) = ln(A) -Ea/RT

Where A is a constant of the reaction, which doesn't depend on the temperature, R is the gas constant (8.314 J/mol.K), and T is the temperature. So, for two different temperatures, if we make the difference between the two equations:

ln(k1) - ln(k2) = ln(A) - Ea/RT1 - ln(A) + Ea/RT2

ln (k1/k2) = (Ea/R)*(1/T2 - 1/T1)

k1 = 8.3x10⁸, T1 = 142.0°C = 415 K

k2 = 6.9x10⁶, T2 = 67.0°C = 340 K

ln(8.3x10⁸/6.9x10⁶) = (Ea/8.314)*(1/340 - 1/415)

4.8 = 6.39x10⁻⁵Ea

Ea = 75078 J/mol

Ea = 75 kJ/mol

4 0
3 years ago
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