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Semenov [28]
2 years ago
12

A frictionless pendulum is made with a bob of mass 19.7 kg. The bob is held at height = 0.934 meter above the bottom of its traj

ectory, and then pushed forward with an initial speed of 2.93 m/s. What amount of mechanical energy does the bob have when it reaches the bottom?
96 J

136 J

265 J

180 J
Physics
1 answer:
Alika [10]2 years ago
4 0

Answer:

265 J

Explanation:

Energy=PE+KE=mgh+ 0.5mv^{2} where KE is kinetic energy, PE is potential energy, m is the mass of an object, v is the speed, h is the height and g is acceleration due to gravity.

Substituting 19.7 Kg for mass, 0.934 for h, 2.93 for v and 9.81 for g then

Energy=19.7(9.81*0.934+0.5*2.93^{2})=265.063303\approx 265 J

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Which of the following is correct concerning the uncontrolled burn phase?
beks73 [17]

The option that is the correct one concerning the uncontrolled burn phase is:

  • The uncontrolled burn phase is characterized by uncontrolled combustion in a cylinder until fuel accumulated during ignition delay is burned.

<h3>What is uncontrolled combustion?</h3>

Uncontrolled Combustion is known to be the the time and place in which a kind of an ignition will stop and it is said to be never  fixed by anything in regards to the compression ignition engine as seen in SI engines.

Note that the four Stages of combustion  are:

1.     Pre-flame combustion

2.     Uncontrolled combustion

3.     Controlled combustion and

4.     After burning

Hence, The uncontrolled burn phase is characterized by uncontrolled combustion in a cylinder until fuel accumulated during ignition delay is burned as all the fuel need to burn out.

Learn more about burn phase from

brainly.com/question/14414049

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7 0
1 year ago
A cylindrical tube sustains standing waves at the following frequencies: 600 Hz, 800 Hz, and 1000 Hz. The tube does not sustain
Thepotemich [5.8K]

Answer:

Explanation:

In  closed organ pipe notes with odd harmonics are produced and in open organ pipe notes with all odd and even harmonics are produced. notes with frequencies 600, 800 and 1000 Hz are produced. These are 3 , 4 and 5 times 200 Hz. ie both odd and even times of 200 . So fundamental frequency appears to be 200 Hz. There is no note available between 800 and 1000. It also indicates that 200 Hz is the fundamental frequency and the pipe is open at both ends.

3 0
3 years ago
Through which medium is it impossible to transmit sound waves?.
dusya [7]

Answer: vacuum

Explanation: The vacuum is the medium from where the sound wave cannot pass. A vacuum is basically an area without any air. Since the sound wave is a mechanical wave that's why it cannot travel through a medium where there is no matter of vibrations to works in, i.e, it can't travel through a vacuum.

4 0
2 years ago
1-Calculate Req
ArbitrLikvidat [17]

Answer:

1. 21.66 Ohms

2.  3.38 A

3. 6.7 V

Explanation:

1. Req = 6+2 = 8 Ohms (2 and 6 are in a series circuit)

  Req = 1/8 +1/4 = 3/8 = 8/3 = 2.66 Ohms (8 and 4 are parallel, so we will add them using this equation)

  Req = 2.66 + 1 + 9 + 3 + 6 = 21.66 Ohms

2. I = V/R = 9/2.66 = 3.38 A (In a series circuit, the current is the same across the resistors, so we will add them and divided them by 9 volts)

3. V = IR = 3.38 x 2 = 6.7 V (In a series circuit, the voltage is different, so each resistor will have a different voltage.)

I hope this helps.  I am not an expert in physics but its ok :)

<u><em>Note: If the answer benefited u, mark me as the brainliest answer if u can, thx.</em></u>

3 0
2 years ago
A force of 100. newtons is used to move an object a distance of 15 meters with a power of 25 watts. Find the time it takes to do
Flauer [41]
<h3>It takes 60 seconds to do the work</h3>

<em><u>Solution:</u></em>

Given that,

Force = 100 newtons

Distance = 15 meters

Power = 25 watts

To find: time it takes to do the work

<em><u>Find the work done:</u></em>

work = force \times displacement\\\\work = 100\ newtons \times 15\ meters\\\\work = 1500\ joule

<em><u>Find the time taken</u></em>

power = \frac{work}{time}\\\\25\ watts = \frac{1500\ joule}{time}\\\\time = \frac{1500\ joule}{25\ watt}\\\\time = 60\ second

Thus it takes 60 seconds to do the work

3 0
3 years ago
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