Answer:
Option A. 1 bar = 1 atm
Explanation:
Pressure has various units of measurement. Each unit of measurement can be converted to other units of measurement. For example:
1 atm = 1 bar
1 atm = 760 mmHg
1 atm = 760 torr
1 atm = 1×10⁵ N/m²
1 atm = 1×10⁵ Pa
With the above conversion scale we can convert from one unit to the other.
Considering the question given above, it is evident from the coversion scale illustrated above that only option A is correct.
Thus,
1 bar = 1 atm
A charge-coupled device (CCD) is a light-sensitive integrated circuit that captures images by converting photons to electrons.
A touch screen is a computer display screen that is also an input device. The screens are sensitive to pressure; a user interacts with the computer by touching pictures or words on the screen.
The similarity is the sensitivity.
The difference is CCD scans or ‘takes images’, whereas touch-screen is where a user interacts with the software.
Hope this helps!
Please give Brainliest!
Answer:
Follows are the solution to this question:
Explanation:
In point a:
Place of particles






In point b:
when 
the Particle velocity
In point c:
Calculating the Particle acceleration:

Pull over the side and stop until it passes you. (my opinion)