3 years ago

A violin string that is 50.0 cm long has a fundamental frequency of 440 Hz. What is the

Physics

2 answers:

DENIUS [597]3 years ago

8 0

Answer:

30800 m/s

Explanation:

correct answer

amid [387]3 years ago

5 0

For a standing wave on a string, the wavelength is equal to twice the length of the string:
$\lambda=2 L$
In our problem, L=50.0 cm=0.50 m, therefore the wavelength of the wave is
$\lambda = 2 \cdot 0.50 m = 1.00 m$

And the speed of the wave is given by the product between the frequency and the wavelength of the wave:
$v=\lambda f = (1.00 m)(440 Hz)=440 m/s$

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