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Alex_Xolod [135]
3 years ago
9

A violin string that is 50.0 cm long has a fundamental frequency of 440 Hz. What is the

Physics
2 answers:
DENIUS [597]3 years ago
8 0

Answer:

30800 m/s

Explanation:

correct answer

amid [387]3 years ago
5 0
For a standing wave on a string, the wavelength is equal to twice the length of the string:
\lambda=2 L
In our problem, L=50.0 cm=0.50 m, therefore the wavelength of the wave is
\lambda = 2 \cdot 0.50 m = 1.00 m

And the speed of the wave is given by the product between the frequency and the wavelength of the wave:
v=\lambda f = (1.00 m)(440 Hz)=440 m/s
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