The first three harmonics of the string are 131.8 Hz, 263.6 Hz and 395.4 Hz.
<h3>
Velocity of the wave</h3>
The velocity of the wave is calculated as follows;
v = √T/μ
where;
- T is tension
- μ is mass per unit length = 2 g/m = 0.002 kg/m
v = √(50/0.002)
v = 158.1 m/s
<h3>First harmonic or fundamental frequency of the wave</h3>
f₀ = v/λ
where;
f₀ = v/2L
f₀ = 158.1/(2 x 0.6)
f₀ = 131.8 Hz
<h3>Second harmonic of the wave</h3>
f₁ = 2f₀
f₁ = 2(131.8 Hz)
f₁ = 263.6 Hz
<h3>Third harmonic of the wave</h3>
f₂ = 3f₀
f₂ = 3(131.8 Hz)
f₂ = 395.4 Hz
Thus, the first three harmonics of the string are 131.8 Hz, 263.6 Hz and 395.4 Hz.
Learn more about harmonics here: brainly.com/question/4290297
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Answer:
The time is
Explanation:
Given that,
Capacitor = 120 μF
Voltage = 150 V
Resistance = 1.8 kΩ
Current = 50 mA
We need to calculate the discharge current
Using formula of discharge current
Put the value into the formula
We need to calculate the time
Using formula of current
Put the value into the formula
Hence, The time is
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spread out over a large enough area that it doesn’t do much more than
leave footprints in a lot of gardens. A slight pulse of pressure spreads
through the North American continental crust and dissipates with little
effect. The sound of all those feet hitting the ground creates a loud,
drawn-out roar which lasts many seconds.
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Answer:
IT doesnt push down because the lawnmower has wheels and the ground is hard
Explanation:
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