1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna71 [15]
3 years ago
7

A: hydrogen and hydrogen b: copper and copper c: copper and oxygen Rank the above bonds in terms of increasing bond strength. Ch

oices A: a
Physics
1 answer:
pashok25 [27]3 years ago
5 0

Answer: Copper and oxygen

Explanation:

Copper and oxygen shares the ionic bond. As we know that ionic bond is the most strongest bond. Here is the order:

Hydrogen bond< Metallic bond< Ionic bond.

That means order in terms of increasing bond strength is :

Hydrogen and hydrogen< Copper and copper< Copper and oxygen.

You might be interested in
When you start the simulation, there is no friction and no air resistance ("Air Drag"). Apply full force to the right, 200N. Wil
kakasveta [241]

Answer:Like friction, the drag force always opposes the motion of an object. ... The drag coefficient can depend upon velocity, but we will assume that it is a ... At highway speeds, over 50% of the power of a car is used to overcome air drag. ... A zero net force means that there is no acceleration, as given by Newton's second law.

3 0
3 years ago
A 1500 kg sedan goes through a wide intersection traveling from north to south when it is hit by a 2500 kg SUV traveling from ea
kolezko [41]

Answer:

v = 19.33 m / s   South

Explanation:

To solve this exercise we must use the conservation of momentum, for which we must define a system formed by the two cars, therefore the forces during the collision are internal and therefore the moment is conserved.

Since it is a vector quantity, we are going to work on each axis, the x axis is in the East-West direction

initial instant. Before the crash

        p₀ = m 0 + M v₂ₓ

final instant. Right after the crash

        p_f = (m + M) vₓ

        p₀ = 0_pf

        M v₂ₓ = (m + M) vₓ

In this case m is the mass of the car and M the mass of the SUV

        vₓ = \frac{M}{m+My}  v₂ₓ            (1)

in the Y axis (North - South direction)

initial instant

       p₀ = m v_{1y} + M 0

final moment

       p_f = (m + M) v_y

       p₀ = p_f

       m v_{1y} + M 0 = (m + M) v_y

       v_y = \frac{m}{m+M}  \  v_{1y}       (2)

With these speeds we can use the relationship between work and the variation of kinetic energy, in this part the two cars are already united.

         W = ΔK

friction force work is

         W = - fr d

the friction force is described by the equation

         fr = μ N

Newton's second law

         N-W = 0

         N = W

         

we substitute

         W = - μ (m + M) g d

as the car stops the final kinetic energy is zero and

the initial kinetic energy is

         K₀ = ½ (m + M) v²

we substitute

         - μ (m + M) g d = 0 - ½ (m + M) v²

            μ g d = ½ v²

            v² = 2 μ g d

the distance traveled can be found with the Pythagorean theorem

        d = \sqrt{x^2+y^2}

        d = \sqrt{5.48^2 + 6.37^2}

        d = 8.40 m

let's calculate the speed

         v² = 2 0.75 9.8 8.40

         v = √123.48

         v = 11.11 m / s

this velocity is in the direction of motion so we can use trigonometry to find the angles

          tan θ = y / x

          θ = tan⁻¹ y / x

          θ = tan⁻¹ (-5.48 / -6.37)

          θ = 40.7º

Since the two magnitudes are negative, this angle is in the third quadrant, measured from the positive side of the x-axis in a counterclockwise direction.

          θ'= 180 + 40.7

          θ’= 220.7º

In the exercise they indicate the the sedan moves in the y-axis, therefore

          sin θ'= v_y / v

          v_y = v sin 220.7

          v_y = 11.11 sin 220.7

          v_y = -7.25 m / s

the negative sign indicates that it is moving south

To find the speed we substitute in equation 2

          v_y = \frac{m}{m+M}  \ v_{1y}

          v_{1y} = v_ y   \frac{m+M}{m}

           

let's calculate

         v_{1y} = -7.25    \frac{1500+2500}{1500}

         v_{1y} = - 19.33 m/s

therefore the speed of the sedan is v = 19.33 m / s with a direction towards the South

4 0
3 years ago
The metric unit of force is the _____.<br><br> A.newton<br> B.pound<br> C.kilogram<br> D.watt
arsen [322]

A force is calculated in neutons

8 0
3 years ago
What is the velocity of a rock that is 0.02 kg and has 36 J of
tatiyna

Answer: 60 m/s

Explanation:

KE = 1/2mv^2

v = √ (2KE / m)

v = √ (2 x 36 J)/(0.02 kg)

v = √ 72 J/0.02 kg

v = √ 3600 m/s

v = 60 m/s

4 0
3 years ago
1. Wind<br> A. Definition<br> B. What Heat Transfer Causes <br> c. Types
mart [117]

Answer:

B . a heat transfer caused

3 0
3 years ago
Other questions:
  • A car slows down uniformly from a speed of 22.0 m/s to rest in 5.50 s. how far did it travel in that time?
    14·2 answers
  • Confidence intervals for the population mean μ and population proportion p _____ as the size of the sample increases.
    14·1 answer
  • A spherical surface completely surrounds a collection of charges. Find the electric flux (with its sign) through the surface if
    9·1 answer
  • A fixed 11.2-cm-diameter wire coil is perpendicular to a magnetic field 0.53 T pointing up. In 0.10 s , the field is changed to
    12·1 answer
  • How does activity on the Sun affect natural phenomena on Earth?
    5·1 answer
  • A woman lifts her 150 N child up one meter and carries her for a distance of 50 meters to the
    15·1 answer
  • What is the distance traveled by an object that moves with an average speed of 6.0 meters per second for 8.0 seconds
    15·1 answer
  • (Power Cycle)​ Your new boss announces at a team meeting that she has developed atechnology that will perform a power cycle that
    12·1 answer
  • Two planets have masses 2 x 10^23 kg and 5 x 10^22 kg, and the distance between them is 3 x 10^16 m. Calculate the gravitational
    12·1 answer
  • PLEASE HELP I WILL MARK YOU
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!